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NISA [10]
2 years ago
6

Josh has 4 times as many pears as leya, who has one half as many pears as amy. If josh has 32 pears how many does amy have?

Mathematics
2 answers:
arlik [135]2 years ago
6 0
<h3>The number of pears Amy has is 16.</h3>

Step-by-step explanation:

Let J represent the number of pears Josh has.

Let L represent the number of pears Leya has.

Let A represent the number of pears Amy has.

From the question given above,

Josh (J) = 4 × Leya (L)

J = 4L ....... (1)

Leya (L) = ½ × Amy (A)

L = ½A ........ (2)

Next, we shall determine the number of pears Leya has. This can be obtained as follow:

From equation 1

J = 4L

But

Josh (J) = 32 pears

Thus,

32 = 4L

Divide both side by 4

L = 32 / 4

<h3>Leya (L) = 8 pears </h3>

Finally, we shall determine the number pears Amy has. This can be obtained as follow:

From equation 2

L = ½A

But

Leya (L) = 8 pears

Thus,

8 = ½A

Cross multiply

A = 8 × 2

<h3>Amy (A) = 16 pears </h3>

Therefore, Amy has 16 pears.

Learn more: brainly.com/question/20971657

uranmaximum [27]2 years ago
4 0

Answer:

josh = 32

leya = 8

amy =4

Step-by-step explanation:

32 pears

Josh = 4l

leya = a/2

Amy = ?

L =8

A = 4

<u><em>Check answer: </em></u>

josh = 32

leya = 8

amy =4

Josh has 4 times as Leya True

Leya has half as many pears as Amy True

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Write the equation of the line that is parallel to y=3x+1 that passes through (2,3)
FromTheMoon [43]

Answer:

Y=3X+3

Step-by-step explanation:

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5 0
3 years ago
2x^3-x^2-3x=210<br> the answer is 5 but I want to know why.
mel-nik [20]

Answer:

x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

Step-by-step explanation:

1) Move all terms to one side.

2x^{3} -x^{2} -3x-210=0

2) Factor 2{x}^{3}-{x}^{2}-3x-210 using Polynomial Division.

1 -  Factor the following.

2x^{3} -x^{2} -3x-210

2 -  First, find all factors of the constant term 210.

1,2,3,4,5,6,7,10,14,15,21,30,35,42,70,105,210

3) Try each factor above using the Remainder Theorem.

Substitute 1 into x. Since the result is not 0, x-1 is not a factor..

2*1^{3} -1^{2} -3*1-210=-212

Substitute -1 into x. Since the result is not 0, x+1 is not a factor..

2(-1)^{3} -(-1)^{2} -3*-1-210=-210

Substitute 2 into x. Since the result is not 0, x-2 is not a factor..

2*2^{3} -2^{2} -3*2-210=-204

Substitute -2 into x. Since the result is not 0, x+2 is not a factor..

2{(-2)}^{3}-{(-2)}^{2}-3\times -2-210 = -224

Substitute 3 into x. Since the result is not 0, x-3 is not a factor..

2\times {3}^{3}-{3}^{2}-3\times 3-210 = -174

Substitute -3 into x. Since the result is not 0, x+3 is not a factor..

2{(-3)}^{3}-{(-3)}^{2}-3\times -3-210 = -264

Substitute 5 into x. Since the result is 0, x-5 is a factor..

2\times {5}^{3}-{5}^{2}-3\times 5-210 =0

------------------------------------------------------------------------------------------

⇒ x-5

4)  Polynomial Division: Divide 2{x}^{3}-{x}^{2}-3x-210  by x-5.

                                               2x^{2}                       9x                      42

                                      -------------------------------------------------------------------------

x-5                               |    2x^{3}                          -x^{2}                     -3x     -210

                                           2x^{3}                             -10x^{2}

                                        -----------------------------------------------------------------------

                                                                             9x^{2}                -3x       -210

                                     --------------------------------------------------------------------------

                                                                          42x                              -210

                                                                         42x                               -210

                                      -------------------------------------------------------------------------

5)  Rewrite the expression using the above.

2x^2+9x+42

(2x^2+9x+42)(x-5)=0

3) Solve for x.

x=5

4)  Use the Quadratic Formula.

1 - In general, given a{x}^{2}+bx+c=0 , there exists two solutions where:

x=\frac{-b+\sqrt{b^{2} -4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}

2 -  In this case, a=2,b=9 and c = 42.

x=\frac{-9+\sqrt{9^2*-4*2*42} }{2*2} ,\frac{-9-\sqrt{9^2-4*2*42} }{2*2}

3 - Simplify.

x=\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

5) Collect all solutions from the previous steps.

x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

4 0
2 years ago
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Which expression is equivalent to 3(x + 4)?
Klio2033 [76]

Answer:

3x + 12

Step-by-step explanation:

Use the distributive property.

3(x + 4) = 3 * x + 3 * 4 = 3x + 12

Answer: 3x + 12

3 0
2 years ago
Read 2 more answers
the sum of two numbers is 70. the larger number is five less than twice the smaller number . what are the two numbers
earnstyle [38]
X+y=70
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y=smaller number
now plug in the value of x to only have one variable in the equation...
Way to solve for y:
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add 5 on both sides...
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divide by 3 on both sides
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1st way to solve for x:
now plug in y in the original equation...
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2nd way to solve for x:
plug in y for the second equation...
x=25(2)-5
x=50-5
x=45
answer: the two numbers are 45 and 25.

3 0
3 years ago
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