Answer:
this is the answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
x-intercept → Plug in 0 for <em>y</em><em> </em>to get −3 for <em>x</em>
y-intercept → When <em>x</em><em> </em>is set equal to 0 [(0, −6)]
I am joyous to assist you anytime.
Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
Step-by-step explanation:
Two lines that are perpendicular to each other has -1 as the product of thir gradient.
Since the gradient of the line y = 3 - x is -1, the gradient of the other line must be 1.
So y = x + c.
When x = 7, y = 1. 1 = 7 + c, c = -6.
Hence the equation of the line is y = x - 6.
