X+y = 4, therefore y = 4-x when you rearrange the equation.
You can subsitute this in: x-(4-x) = 6
-4+x = 6-x
x=10-x
2x = 10
x = 5
Substitute x into the previous equation:
5+y = 4
y = 4-5
y = -1
Answer:
You are a lazy Bum!!!!!
Step-by-step explanation:
You are a lazy Bum!!!!!You are a lazy Bum!!!!!
Answer:
Step-by-step explanation:
No they are binomial as X is common variable two times and there is one number
4 1/4, 4 5/12, 4 2/3. Not sure if there is suppose to be a 4 in front of the 5/12 but if there is this is how it should be ordered
Answer:
b)(b²-a²)
Step-by-step explanation:
a cotθ + b cosecθ =p
b cotθ + a cosecθ =q
Now,
p²- q²
=(a cotθ + b cosecθ)² - (b cotθ + a cosecθ)² [a²-b²=(a+b)(a-b)]
=(acotθ+bcosecθ + bcotθ+ acosecθ) (a cotθ + bcosecθ -bcotθ-acosecθ)
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ)+b (cosecθ-cotθ)}
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} [a (cotθ-cosecθ) + {- b (cotθ-cosecθ)} ]
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ) - b (cotθ-cosecθ)}
={(cotθ+cosecθ)(a+b)} {(cotθ-cosecθ) (a-b)}
=(cotθ+cosecθ) (a+b) (cotθ-cosecθ) (a-b)
=(cotθ+cosecθ) (cotθ-cosecθ) (a+b) (a-b)
= (cot²θ-cosec²θ) (a²-b²) [(a+b) (a-b)= (a²-b²)]
= -1 . (a²-b²) [ 1+cot²θ=cosec²θ ; ∴cot²θ-cosec²θ=-1]
=(b²-a²)
