Answer: 7/10, 7/10 and 3/10.
Step-by-step explanation:
7/10 = Between 1 and 10, the multiples of three are 3, 6, and 9. So the amount favourable outcomes is the total minus the multiples, 10-3 = 7. So 7/10.
7/10 = Between 1 and 10, the multiples of 2 are 2, 4, 6, 8, and 10. The multiples of 3 are 3, 6 and 9. That, gives 7 favourable outcomes (6 is a multiple of both but counted once) giving the probability of 7/10.
3/10 = The favourable outcome is 8 and above, so: 8, 9 and 10. There are 3 favourable outcomes which gives the probability of 3/10.