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Blababa [14]
3 years ago
5

after 20 minutes he is on page 151, after 45 minutes he was on page 181. how many pages had clint read prior to study hall

Mathematics
1 answer:
xeze [42]3 years ago
6 0
127 is the answer bc if you subtract 45-20 that gives you 25 minutes and then in 25 minutes he read 30 pages so you can divide 30÷25 which gives you 1.2 so then you’re going to multiply 20 and 1.2 which gives u 25 and subtract 24 from 151
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We define the probability of a particular event occurring as:
\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have \frac{3}{36} = \frac{1}{12} probability of rolling at least one 5.
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A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta
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Answer:

\dfrac{11}{30}

Step-by-step explanation:

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Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

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The probability to choose each urn is the same and is equal to \frac{1}{3}.

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\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.

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