3 1/2 divided by 2 1/4 = 1.55555556
1.55555556 Rounded is 1.55
8 1/2 or 8.5 x11 = 93.5 square inches thus,
1000 square inches divided by 93.5 square inches
1000/93.5 ~10.695
that mean that Jodi can cut out about 10 pieces of paper measuring 8 1/2 x 11 inches.
3 1/2 ÷ 1 1/4
7/2 ÷ 5/4
7/2 · 4/5
28/10
2.8
Julio walks 2.8 miles in one hour.
Answer:
6x^2 (3x^2 - 2)
Step-by-step explanation:
18x^4 - 12x^2
6x^2 (3x^2 - 2)
Answer:
The passing score is 645.2
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 553, \sigma = 72](https://tex.z-dn.net/?f=%5Cmu%20%3D%20553%2C%20%5Csigma%20%3D%2072)
If the board wants to set the passing score so that only the best 10% of all applicants pass, what is the passing score?
This is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![1.28 = \frac{X - 553}{72}](https://tex.z-dn.net/?f=1.28%20%3D%20%5Cfrac%7BX%20-%20553%7D%7B72%7D)
![X - 553 = 1.28*72](https://tex.z-dn.net/?f=X%20-%20553%20%3D%201.28%2A72)
![X = 645.2](https://tex.z-dn.net/?f=X%20%3D%20645.2)
The passing score is 645.2