Trish is correct because whatever number starts the tree equals 48 anyway. The numbers that matters is if you follow through when factoring out the whole tree of 48.
Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
We know that
In French club <span>there are
10 freshman
</span><span>12 sophomores
15 juniors
30 seniors
total of the members------> (10+12+15+30)=67
total </span> freshman-----> 10
so
<span>the probability that a freshman will be chosen=10/67
and
</span><span>the probability that a freshman will not be chosen=(67-10)/67
</span>the probability that a freshman will not be chosen=57/67---> 0.8507
0.8507= 85.07%
the answer is
the probability that a freshman will not be chosen is 85.07%
Answer:
(3/2,0)
Step-by-step explanation:
Substitute 0 for y and solve for x
Answer: first to tell you how to do it we start with y=mx=b or y1-y2/x1-x2 then put the values in. and slove for y
Step-by-step explanation:
