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3 years ago

Think About the Process A restaurant customer left $1.10 as a tip. The tax was 8% and the tip was

Mathematics

1 answer:

harkovskaia [24]3 years ago

3 0

Answer:

Step-by-step explanation:

All of them.

Hope this helps :D

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AYO HELP ME WITH THIS!!!!

xeze [42]

Answer:

a taco is 1.25 and a drink is 0.95

Step-by-step explanation:

tacos = t

drinks = d

5t + 3d = 9.10

3t + d = 4.70

this is a simultaneous equation so times the first one by one and the second by 3 and then take them away from each other and solving to get

t = 1.25 and d=0.95

one drink is $0.95

one taco is $1.25

Hope this helps!!

4 0

3 years ago

swame and luigi were printing calendars swame used 21/2 cartridge, while luigi used 1 3/4 ink cartridges. how many more ink cart

nirvana33 [79]

I’m not sure if this is correct but the answer would be 8.75 well that’s what I got hope this helps and if it dead pls give me a thanks

8 0

3 years ago

suppose a car is traveling southwest on king avenue and turns left onto 3rd street. what is the measure of the angle created by

dem82 [27]

Answer: The angle is 105 degrees. This angle along with the 75 degree angle make a straight line , 180-75 = 105 degrees

4 0

3 years ago

Rachel frank and Austin sent a total of 68 text messages during the weekend Rachel sent 7 fewer messages than Austin frank sent

elena-14-01-66 [18.8K]

Answer:I think 183

Step-by-step explanation:

3 0

3 years ago

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

5 0

3 years ago