$\bf 2log(x-3)+1=5\iff 2log_{10}(x-3)+1=5\\\\\\ 2log_{10}(x-3)=4
\\\\\\
log_{10}(x-3)=\cfrac{4}{2}\implies log_{10}(x-3)=2\\\\
-----------------------------\\\\
{{ a}}^{log_{{ a}}x}=x\impliedby \textit{using this cancellation rule}\\\\
-----------------------------\\\\
10^{\cfrac{}{}log_{10}(x-3)}=10^2\implies x-3=10^2\implies x=100+3$

5 0

3 years ago

Helppppppppppppppppppppppppppppppppp

liq [111]

Answer:

The answer is B

you should still invest in a calculator (:

4 0

2 years ago

What is 7n + 3 = 3n + 27

icang [17]

7n + 3 = 3n + 27

7n -3n =27-3
4n =24
n= 6.

4 0

2 years ago

X^2−10x−96 rewrite the function by completing the square (x+___)^2+_____ thanks! *^*

X^2−10x−96 rewrite the function by completing the square (x+_)^2+___ thanks! ^