<span>Resistors are said to be connected in series when they are daisy chained together in a single line. The serial circuit of resistors result has a common current flowing through the resistors.
</span><span>The current that flows through one resistor must also flow through the others.
</span>
The total equivalent resistance, is given as:
<span>Rtotal = R1 + R2 + R3 , where R1 is the resistance of the first resistor, R2 of the second and R3 f the third</span>
Answer:
The code is as follows:
for(int j = 0; j < newScores.length-1; j++){
newScores[j] = oldScores[j+1];
}
newScores[oldScores.length-1] = oldScores[0];
Explanation:
This loop iterates through the elements of oldScores
for(int j = 0; j < newScores.length-1; j++){
This enters the elements of oldScores to newScores starting from the element at index 1
newScores[j] = oldScores[j+1];
}
This moves the first element of index 0 to the last index of newScores
newScores[oldScores.length-1] = oldScores[0];
