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stealth61 [152]
3 years ago
15

Select all tables that represent a proportional relationship between X and Y

Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer:

The 'constant of proportionality k' DOES NOT remain constant for all the points in the table.

Therefore, the table DOES NOT represent a proportional relationship between X and Y.

Step-by-step explanation:

We know that when y varies directly with x, we get

y ∝ x

y = kx

k = y/x

where k is called the 'constant of proportionality'.

Given the table

x         0          5           10             15

y         2         17           32             47

Let us calculate the k value for all the points

FOR (0, 2)

k = y/x

substitute x = 0, and y = 2

k = 2 / 0 = ∞

FOR (5, 17)

k = y/x

substitute x = 5, and y = 17

k = 17/5

k = 3.4

FOR (10, 32)

k = y/x

substitute x = 10, and y = 32

k = 32/10

k = 16/5

k = 3.2

FOR (15, 47)

k = y/x

substitute x = 15, and y = 47

k = 47/15

k = 3.1

It is clear that the 'constant of proportionality k' DOES NOT remain constant for all the points in the table.

Therefore, the table DOES NOT represent a proportional relationship between X and Y.

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The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

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What is the simplified form of 4 x 6^2 ÷ 3 + 7? ​
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72/5 or 14.4 hope this helped you
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frank reasoned that in the number 0.555, the valueof the 5 in the thousandths place is ten times the value of the 5 in the hundr
ollegr [7]

The reasoning of Frank is not correct. The value of 5 is the thousandths place is 1/10 times the value of 5 in the hundredths place instead of being 10 times.

In the question, we are given the number 0.555.

We can write it as:-

0.555 = 0.500 + 0.050 + 0.005

0.500 is the value of tenths place

0.050 is the value of hundredths place

0.005 is the value of thousandths place

We know that,

0.050*(1/10) = 0.050/10 = 0.005

Hence, the value of 5 is the thousandths place is 1/10 times the value of 5 in the hundredths place.

To learn more about thousandths place, here:-

brainly.com/question/21467438

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