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3 years ago

I need help pleases and ASAP

Mathematics

2 answers:

katen-ka-za [31]3 years ago

7 0

A or C

I don't know completely cause I don't have enough information but I do know its one of those.

Ivanshal [37]3 years ago

4 0

Answer:

The answer would be D .

Step-by-step explanation:

Hope it was helpful . ♡

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Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are

Svetlanka [38]

Answer:

(a) Number of sets B given that

A⊆B⊆C: 2¹⁰. (That is: A is a subset of B, B is a subset of C. B might be equal to C)
A⊂B⊂C: 2¹⁰ - 2. (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

Let $x_1, x_2, \cdots, x_{20}$ denote the 20 elements of set X.

Let $x_1, x_2, \cdots, x_{10}$ denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain $x_1, x_2, \cdots, x_{10}$ .

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from $x_1, x_2, \cdots, x_{20}$ .

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves $2^{10} -2 = 1024 - 2 = 1022$ possibilities.

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

$\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}& \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}$ .

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus $2^{10} = 1024$ possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's $2^{20} = 1048576$ possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only $2^{20} - 2^{10}$ possibilities left.

5 0

2 years ago

Please answer this correctly without making mistakes

Monica [59]

Answer:

g=56

Step-by-step explanation:

In similar shapes, corresponding sides are always in the same ratio.

For example,

if the sides in triangle 1 were a and b, and triangle 2 had side lengths c and d, c and a had the same ratios, and b and d had the same ratios

and triangle 1 was similar to triangle 2, the ratio between the sides of the triangles would be

a/c, which is also equal to b/d

What that means is that in this situation, 8/5=g/35.

8/5=g/35

Cross multiply.

(8)*(35)=g*(5)

280=5g

g=56

4 0

3 years ago

two friends bought a $14 pizza. Each person bought their own drink. The total cost of the food can be represented by the express

yanalaym [24]

The expression might be x=7

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2 years ago

4. The mode of the following data set is 15, 16, 17, 23. 11, 19, 20, 15, 18, 22. 15, 19

ASHA 777 [7]

ANSWER ↓

========================

u can download the gauthmath app i promise it's very helpful here's the code if needed <u>3AFJF9</u>

<em>trust</em><em> me</em><em> its</em><em> very</em><em> helpful</em><em> </em><em>:</em><em>)</em>

7 0

3 years ago

Read 2 more answers

Challenge A large university accepts 60% of the students who apply. Of the students the university

Irina-Kira [14]

Answer:

man i cant really say

Step-by-step explanation:

7 0

2 years ago