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3 years ago

15

Mia cut a piece of felt into 3 equal

1 answer:

morpeh [17]3 years ago

4 0

Answer:

$\frac{1}{3}$

Step-by-step explanation:

Mia used One Third of the felt for her art project. 3/3 would be the whole felt together. Since one part of three sections was used up then this means that 1/3 was used.

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Find the surface area of the composite solid.

Westkost [7]

We have:

4 triangles with the base b = 5ft and the height h = 6ft

4 rectangles with the lenght l = 5ft and the width w = 4ft

1 square with side a = 5ft.

The formula of an area of a riangle:

$A_T=\dfrac{1}{2}bh$

Substitute:

$A_T=\dfrac{1}{2}(5)(6)=\dfrac{1}{2}(30)=15\ ft^2$

The formula of an area of a rectangle:

$A_R=lw$

Substitute:

$A_R=(5)(4)=20\ ft^2$

The formula of an area of a square:

$A_S=a^2$

Substitute:

$A_S=5^2=25\ ft^2$

The Surface Area of composite solid:

$SA=4A_T+4A_R+A_S$

Substitute:

$SA=4(15)+4(20)+25=60+80+25=165\ ft^2$

<h3>Answer: The Surface Area of the composite solid is 165 ft².</h3>

3 0

3 years ago

Which quadrilaterals must have both pairs of opposite angles that are congruent?

pashok25 [27]

The correct answer is c

7 0

2 years ago

What is the average score of runa 140,96 and 13?

scoundrel [369]

$\huge\textsf{Hey there!}$

$\large\textsf{Formula:}$

$\mathsf{\dfrac{Sum\ of\ all\ terms}{Total\ number\ of\ values\ in\ the\ data}= your\ mean/average}$

$\mathsf{\dfrac{140+96+13}{3}}$

$\mathsf{140+36+13}$

$\mathsf{140 + 96 = \bf 236}$

$\mathsf{236 + 13}$

$\mathsf{ = \bf 249}$

$\mathsf{\dfrac{249}{3}}$

$\mathsf{= \bf 83}$

$\boxed{\boxed{\large\textsf{Possible answer: \huge \bf 83}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

2 years ago

A triangle has two sides of lengths 7 and 12. What value could the length of the third side be? Check all that apply.

Ulleksa [173]

17 11 9 and 7

Remember that the third side must be greater than 5 and less than 19.

6 0

2 years ago

Read 2 more answers

If n erasers have a weight of 80 grams, what is the total weight of 50 erasers?

Black_prince [1.1K]

Answer:

$The\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.$

Step-by-step explanation:

As given

if n erasers have a weight of 80 grams .

I.e

n erasera = 80 grams.

1 erasers weight .

$1\ erasers\ weight = \frac{80}{n}$

Now find out the weight of the 50 erasers.

$Weight\ of\ 50\ erasers = \frac{50\times 80}{n}\ grams$

Simplify the above

$Weight\ of\ 50\ erasers = \frac{4000}{n}\ grams$

$Therefore\ the\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.$

6 0

3 years ago

Read 2 more answers