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Volgvan
3 years ago
9

x}" alt="\sqrt{50x} - \sqrt{18x}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

Step-by-step explanation:

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Number 4 please !! due tomorrow
Minchanka [31]

Answer:

c is the answer




4 0
3 years ago
Pls help me! I’m so confused on how to do this my teacher isn’t the best at explaining math… I need #4 a,b,c,d answers. Again pl
Ugo [173]

Answer:

I'll answer if u make my Answer Brainliest!!! <33333333

I know the answer btw!

Step-by-step explanation:

Also HII <3

3 0
3 years ago
PLEASE HELP
Oliga [24]

Answer:

The answer your looking for is, <u><em>C.</em></u>

3 0
3 years ago
Read 2 more answers
1).Calculate T, when sample mean is 120, population mean is 100, standard deviation is 20 and smaple size is 10 using levels of
Sonbull [250]

Answer:

t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16  

p_v =2*P(t_{9}>3.16)=0.012  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=120 represent the sample mean  

s=20 represent the standard deviation for the sample

n=10 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is different from 100, the system of hypothesis would be:  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=10-1=9

Conclusion

Since is a tao tailed test the p value would be:  

p_v =2*P(t_{9}>3.16)=0.012  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.  

8 0
3 years ago
Read 2 more answers
The length of a rectangle are represented by consecutive even integers. If the perimeter is 60, find the dimensions
Pachacha [2.7K]

Answer:

Length = 24 and width = 6.

Step-by-step explanation:

2L + 2W = 60 where L = length and W = width.

The length must be in the 20's to make a perimeter of 60, as there's no number in the 10's or 30's that has 2 consecutive even integers and 40 something is impossible.

The only length which fits the given conditions is 24.

Then the width would be (60 -  2(24)) / 2 =  (60 - 48) / 2

= 6.

That's the answer.

7 0
4 years ago
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