Answer:
Answer=B
(f+g)(x)=-3x-5
Step-by-step explanation:
f(x)=x+8.
g(x)=-4x-3.
(f+g)(x) means f(x)+g(x),So
(x+8)+(-4x-3)
(add all same terms together)
=(x+(-4x))+(8+(-3))
=-3x+5
so,
(f+g)(x)=-3x+5
The answer is 3. I don't know if you want ne to explain or show my work just reply to me.
Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
Answer:
The length of the longer base he 35 units
Step-by-step explanation:
Here, we want to find the length of the longer base of the trapezoid
Mathematically, we can find the area using the formula;
1/2( a + b) h
where a is the shorter base
b is the longer base
h is the height
Let the shorter base be x
The other base is 5 times this length and that makes 5 * x = 5x
Height is the average of both bases;
(x + 5x)/2 = 6x/2 = 3x
Substituting these in the formula, we have ;
1/2(x + 5x)3x = 441
3x(6x) = 882
18x^2 = 882
x^2 = 882/18
x^2 = 49
x^2 = 7^2
x = 7
But the longer base is 5x and that will be 5 * 7 = 35 units
Let x = the length of the shorter piece
x+x+16=50in
2x=50-16
2x=34
x=17
Then
x+16=17+16
x+16=33
Subtract 16 from both sides
The lengths are 17in and 33in
