Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
70/(10-3)+1=11
Step-by-step explanation:
simplify
70/(7)+1=11
10+1=11
11=11
Answer:
B
Step-by-step explanation:
The information on the graph is almost symmetrical, because the lines look almost the same length on both sides.
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