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Natali5045456 [20]
2 years ago
7

Part of the student's solution for finding the quotient 288 ÷ 24 is shown below. 240 ÷ 24 = 10 288 – 240 = 48 48 ÷ 24 = 2 Which

step should the student do next? A. 10 + 2 B. 240 ÷ 3 C. 10 + 48 + 2 D. 10 – 2
Mathematics
1 answer:
Neporo4naja [7]2 years ago
6 0

Answer:

A. 10 + 2

Step-by-step explanation:

288 ÷ 24 is shown below. 240 ÷ 24 = 10 288 – 240 = 48 48 ÷ 24 = 2

After obtaining the quotient of 288 ÷ 24 = 10,

Multiplying the divisor 24 by 10 = 240 and subtracting 240 from 288 to obtain the remainder = 48, the divisor is again used in 48 and the quotient obtained is added to the intula quotient value of 10 ; (10 + 2) and the process repeated

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Step-by-step explanation:

9.75/2.5

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Each of the 25 balls in a certain box is either red, blue, or white and has a number from 1 to 10 painted on it. If one ball is
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Answer:

Probability ball: white - P(W)P(W);

Probability ball: even - P(E)P(E);

Probability ball: white and even - P(W&E).

Probability ball picked being white or even: P(WorE)=P(W)+P(E)-P(W&E).

(1) The probability that the ball will both be white and have an even number painted on it is 0 --> P(W&E)=0 (no white ball with even number) --> P(WorE)=P(W)+P(E)−0P(WorE)=P(W)+P(E)−0. Not sufficient

(2) The probability that the ball will be white minus the probability that the ball will have an even number painted on it is 0.2 --> P(W)−P(E)=0.2P(W)−P(E)=0.2, multiple values are possible for P(W)P(W) and P(E)P(E) (0.6 and 0.4 OR 0.4 and 0.2). Can not determine P(WorE)P(WorE).

(1)+(2) P(W&E)=0 and P(W)−P(E)=0.2P(W)−P(E)=0.2 --> P(WorE)=2P(E)+0.2P(WorE)=2P(E)+0.2 --> multiple answers are possible, for instance: if P(E)=0.4P(E)=0.4 (10 even balls) then P(WorE)=1P(WorE)=1 BUT if P(E)=0.2P(E)=0.2 (5 even balls) then P(WorE)=0.6P(WorE)=0.6. Not sufficient.

Answer: E.

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
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Divide both sides by 2
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