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3 years ago

HELP IN A TEST ILL GIVE BRAINLIEST

Mathematics

1 answer:

german3 years ago

8 0

Answer:

Can u send a more clear pic

Step-by-step explanation:

thankyou

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The perimeter of a rectangle is greater than or equal to 74 meters.

Ksju [112]

Answer:

Step-by-step explanation:

First, multiply the length by two then, subtract the total by the sum, last divide by two.

(25 * 2)

(74 - 50)

(24/2)

Answer = 12

5 0

3 years ago

Read 2 more answers

−px+r=−8x−2<br> solve for X

Arlecino [84]

-8x-2=0
-8x=2
8x=-2
x=-1/4

5 0

3 years ago

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(1 point) Consider the function f(x)=−x3+2x2+2x+1 Find the average slope of this function on the interval (−2,6). equation edito

Whitepunk [10]

Answer:

Step-by-step explanation:

Given is a function

$f(x)=-x^3+2x^2+2x+1$

$f(6) = -6^3+2(6^2)+2(6)+1\\=-131\\$

$f(-2) = -(-2)^3+2(-2)^2+2(-2)+1\\=13$

Average slope of this function is change of f(x) in (-2,6)/change of x in (-2,6)

= $\frac{-131-13}{8} \\=-18$

By mean value theorem there exists a c such that f'(c) = -18

i.e. $-3x^2+4x+2 =-8\\3x^2-4x-10 =0\\$

Using quadratic formula

x = 2.61, -1.277

Out of these only 2.61 lies in the given interval

c = 2.61

7 0

3 years ago

Approximate the change in the volume of a sphere when its radius changes from r = 40 ft to r equals 40.05 ft (Upper V (r )equal

alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere ( $V$ ), measured in cubic feet, is represented by the following formula:

$V = \frac{4\pi}{3}\cdot r^{3}$

Where $r$ is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

$\Delta V = \frac{\partial V}{\partial r}\Delta r$

The derivative of the volume as a function of radius is:

$\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}$

Then, the change in volume is expanded:

$\Delta V = 4\pi \cdot r^{2}\cdot \Delta r$

If $r = 40\,ft$ and $\Delta r = 40\,ft-40.05\,ft = 0.05\,ft$ , the change in the volume of the sphere is approximately:

$\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)$

$\Delta V \approx 1005.310\,ft^{3}$

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0

3 years ago

The rule is x→y=−x. Copy and fill in the table with at least 4 points.<br> x l y<br> l<br> l

VikaD [51]

Answer:

is there numbers???

Step-by-step explanation:

5 0

2 years ago