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3 years ago

The greater of two numbers is six more

Mathematics

1 answer:

pickupchik [31]3 years ago

5 0

Answer:

Let's begin by writing the mathematical equations given by the sentences.

Let X = smaller number

Let Y = larger number

The first sentence tells us

X + Y = 38

The second sentence tells us

X = Y/3 + 6

Since you weren't given a specific method to use, you can use either the substitution method or the elimination(addition) method, whichever works best for you.

Since the 2nd equation has the X isolated, I'm going to isolate the X in the first equation,

X = 38 - Y

Since both equations are equal to X, I can set them equal to one another and solve for Y.

Y/3 + 6 = 38 - Y

Y + 18 = 114 - 3Y

4Y = 96

Y = 24

Then use either of the two original equations to solve for X

X + Y = 38

X + 24 = 38

X = 14

Step-by-step explanation:

PLS MAKE ME AS BRAINLIST

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Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the gi

kompoz [17]

Answer:

The general solution is

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2}$

Step-by-step explanation:

Step :1:-

Given differential equation y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

$(D^4 -2D^3+D^2)y = e^x+1$

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

$m^4 -2m^3+m^2 = 0$

$m^2(m^2 -2m+1) = 0$

$(m^2 -2m+1) this is the expansion of (a-b)^2$

$m^2 =0 and (m-1)^2 =0$

The roots are m=0,0 and m =1,1

complementary function is $y_{c} = (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x$

Step 2:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x + \frac{1}{D^{2} } e^{0x}$

$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

$I_{2}$ $= \frac{1}{D^2(D-1)^2}e^{0x}$

$\frac{1}{D} \int\limits {1} \, dx= \frac{1}{D} x$

again integration $\frac{1}{D} x = \frac{x^2}{2!}$

The general solution is $y = y_{C} +y_{P}$

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2!}$

3 0

3 years ago

Two polygons are similar. What is the correct similarity statement?

joja [24]

Answer:

option 3

Step-by-step explanation:

Given the 2 triangles are similar then corresponding angles are congruent.

Calculate the missing angles in both triangles.

∠ A = 180° - (90 + 35)° = 180° - 125° = 55°

∠ L = 180° - (90 + 55)° = 180° - 145° = 35°

Consider ACB ~ MNL , comparing corresponding angles

∠ A= 55° and ∠ M = 90° ← not congruent

Consider ABC ~ LMN, comparing corresponding angles

∠ A = 55° and ∠ L = 35° ← not congruent

Consider CBA ~ LMN , comparing corresponding angles

∠ C = 35° and ∠ L = 35° ← congruent

∠ B = 90° and ∠ M = 90° ← congruent

∠ A = 55° and ∠ N = 55° ← congruent

The correct similarity statement is

CBA ~ LMN

6 0

3 years ago

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The equation of a circle is (x−11)2+(y+15)2=144 . What is the circle's radius?

yuradex [85]

The equation of a circle is (x-h)^2+(y-k)^2=r^2, where (h,k) is the center and r is the radius.
To find the radius, we would find the square root of 144, which is 12.
r=12

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3 years ago

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Which is the graph of g(x) = [X +3]?

Daniel [21]

Answer:

Step-by-step explanation:

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3 years ago

If two rays are opposite rays, then they have a common endpoint.

Ilia_Sergeevich [38]