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pogonyaev
3 years ago
7

[|(x-4)÷(x+5)|]\leq[4]

Mathematics
1 answer:
Katena32 [7]3 years ago
3 0

Answer:

Solutions are;

x = -8

x = -3.2

Step-by-step explanation:

Here, we want to solve the given equation for x

|(x-4)/(x + 5)| = 4

From what we have, this is an absolute value equation and thus, we are going to have two solutions

These are;

x-4/x+ 5 = 4

x-4 = 4(x + 5)

x-4 = 4x + 20

x-4x = 20 + 4

-3x = 24

x = -24/3

x = -8

secondly;

x-4/x+5 = -4

x-4 = -4(x + 5)

x-4 = -4x - 20

x + 4x = -20 + 4

5x = -16

x = -16/5

x = -3.2

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nlexa [21]

Answer:

x = \frac{5}{4}

Step-by-step explanation:

Given

4x + 6 = 11 ( subtract 6 from both sides )

4x = 5 ( divide both sides by 4 )

x = \frac{5}{4} = 1.25

4 0
2 years ago
Read 2 more answers
Check my answer please
Aleksandr [31]
So it is an isosceles triangle that means that the bottom two angles are equal...
so 
40 = 5x 
divide both sides by 5 and you get 8

now the triangle angles add up to 180
we make an equation out of it...
(2y + 20 ) + ( 5(8)) + 40 = 180
2y + 20 + 40 + 40 = 180
combine like terms
2y + 100 = 180
so subtract 100 from both sides
2y = 80
divide by 2 to isolate the variable
y = 40

You are correct!!! :)
5 0
3 years ago
Help me pls I need help asap
Aliun [14]
These two angles are corresponding angles, so x = 136 degrees
8 0
2 years ago
30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 &lt;0
Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

-2logx^3-3

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

-2logx^3-3+3

\mathrm{Simplify}

-2logx^3

Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

6 0
2 years ago
In chemistry, there is a class of compounds called alkanes. They have the general formula 2x+2, where stands for a carbon
mixer [17]

Answer:Alkanes: CnH2n+2

n=8 --> C8H18. So it is 18 atoms

Step-by-step explanation:

8 0
2 years ago
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