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SVEN [57.7K]
3 years ago
14

Elmar bought a new pair of baseball cleats for $65. The sales tax is 5.5%. What is the total cost that Elmar will pay?

Mathematics
1 answer:
mash [69]3 years ago
3 0

Answer:

Final price: $68.58

Tax: $3.58

Step-by-step explanation:

              May I have brainiest I'm trying to level up!

                      </3 PureBeauty

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I think this is the right answer but last two signs are incorrect

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A parent is using a garden hose to fill up a small inflatable pool for her young child. The
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Answer:

The independent is the 90 gallons and the dependent is the 8 minutes.

Hope this helps!

Step-by-step explanation:

7 0
3 years ago
The first and third terms in the following Fibonacci sequence are x and y.
Dahasolnce [82]

Answer:

<h3>The second term of the sequence is y-x</h3><h3>The fourth term of the sequence is 2y-x</h3><h3>The fifth term of the sequence is 3y-x</h3>

Step-by-step explanation:

The next term of a Fibonacci sequence is generated by taking the sum of the 2 preceding value of the sequence. Given the the first and third term of a Fibonacci sequence to be x and y

x, _, y...

let the second term be a, fourth term be b and fifth term be c to have the sequence;

x, a, y, b, c...

According to the definition;

x+a = y... 1

a+y = b... 2 and;

y+b = c... 3

From equation 1, a = y-x

Substituting a = y-x into equation 2 to get b we have;

(y-x)+y = b

2y-x = b

b = 2y-x

Substituting b = 2y-x into equation 3 to get 'c'

y +  2y-x = c

3y-x = c

c = 3y-x

The second term of the sequence is y-x

The fourth term of the sequence is 2y-x

The fifth term of the sequence is 3y-x

8 0
3 years ago
On a particular production line, the likelihood that a light bulb is defective is 10%. seven light bulbs are randomly selected.
amid [387]

Answer:

0.9995

Step-by-step explanation:

10% = 0.10

1 - 0.10 = 0.9

n = number of light bulbs = 7

we calculate this using binomial distribution.

p(x) = nCx × p^x(1-p)^n-x

our question says at most 4 is defective

= (7C0 × 0.1⁰ × 0.9⁷) + (7C1 × 0.1¹ × 0.9⁶) + (7C2 × 0.1² × 0.9⁵) + (7C3 × 0.1³ × 0.9⁴) + (7C4 × 0.1⁴ × 0.9³)

= 0.478 + 0.372 + 0.1239 + 0.023 + 0.0026

= 0.9995

we have 0.9995 probability that at most 4 light bulbs are defective.

6 0
3 years ago
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