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tresset_1 [31]
3 years ago
15

Does anyone have a coursehero account that I can borrow

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0

Answer:

No but an easy way is to just make up random email names and passwords and on each acc u get 5 free questions,

Step-by-step explanation:

Can u pls mark me brainliest

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If M is the midpoint of PQ and X is the midpoint of PM then PX = a PQ Which statement is True? a is equal to 1 a is equal to 1/2
garik1379 [7]

Answer:

D. a is equal to  \frac{1}{4}

Step-by-step explanation:

Let us assume that segment PQ is 8 units, so that its midpoint M is at 4 units to both P and Q.

Given that X is the midpoint of PM, this implies that X is at 2 units to both P and M.

Then;

PX = aPQ

⇒   = a x 8

      = 8a

Therefore, a must be equal to \frac{1}{4}, so that;

PX = 8a

     = 8 x  \frac{1}{4}

     = 2 units

Thus, a is equal to  \frac{1}{4} is the correct option.

6 0
4 years ago
A rectangular prism has a length of 8 in., a width of 4 in., and a height of 2 1/4 in. The prism is filled with cubes that have
wariber [46]
The prism is (8 in)/(1/4 in/cube) = 32 cubes by (4 in)/(1/4 in/cube) = 16 cubes by (9/4 in)/(1/4 in/cube) = 9 cubes.

The number of cubes needed to fill the prism is
.. 32 * 16 * 9 = 4608
7 0
4 years ago
11111111111111111111111111111111111111111111111111111111111111111111111111111111111
kramer

Answer:

what do we have to do

Step-by-step explanation:

8 0
4 years ago
Find the area of a triangle whose vertices are located at (-2,5), (-4, -3), and (3,1). Evaluate the determinant using diagonals.
myrzilka [38]

Answer:

The area of the triangle is 48 unit²

Step-by-step explanation:

The given vertices of the triangle are;

(-2, 5), (-4, -3), and (3, 1)

The formula for finding the area of a triangle with given coordinates of the vertices is as follows;

\Delta  = \dfrac{1}{2}\times \begin{vmatrix}x_1 & y_1 & 1\\ x_2 & y_2 & 1\\ x_3 & y_3 & 1\end{vmatrix} = \dfrac{1}{2}\times \left | x_1\cdot y_2 - x_2\cdot y_1 + x_2\cdot y_3 - x_3\cdot y_2 + x_3\cdot y_1 - x_1\cdot y_3\right |

Substituting gives;

\Delta  = \dfrac{1}{2}\times \begin{vmatrix}-2& 5 & 1\\ -4 & -3 & 1\\ 3 & 1 & 1\end{vmatrix} \\\Delta  = \dfrac{1}{2}\times \left | (-2)\times (-3) - ((-4)\times 5) + (-4)\times 1 - 3\times (-3) + 3 \times 5 - (-2)\times 1\right | \\\Delta  = \dfrac{1}{2}\times \left | 6 +20 -4 +9 + 15+2\right |  = 48

The area of the triangle = 48 unit².

5 0
3 years ago
Solve the equation, x^2+3x+1=0, using the quadratic formula.
kari74 [83]

Answer:

x = (-3±√5)/2

Step-by-step explanation:

Matching the given equation to the pattern ...

... ax² +bx +c = 0

we see that a=1, b=3, c=1.

The solution to the above pattern is given by the quadratic formula ...

... x = (-b±√(b²-4ac))/(2a)

Substituting the values of a, b, c that we found, the formula gives ...

... x = (-3±√(3²-4·1·1))/(2·1)

... x = (-3±√5)/2

7 0
4 years ago
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