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3 years ago

7. Newton buys a board game for $9.99

Mathematics

1 answer:

miv72 [106K]3 years ago

7 0

Answer: Hello, there! Your Answer is Below^^

7.O2 Would be The Correct Answer.

Step-by-step explanation:

So I Subtracted 20 - 12.98 And Got the Answer $ 7.02

To Add Or subtract Decimals Here's what you can do to find your Answer

Line up the numbers vertically so that the decimal points all lie on a vertical line.

Add extra zeros to the right of the number so that each number has the same number of digits to the right of the decimal place. Step 3: Subtract the numbers as you would whole numbers.

Hope this Helps!!

Have a great day!!!

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Find the value of x that will make L||M. Please help me on this one!!!!!!! I need this done.

Galina-37 [17]

The given angles are known as alternate interior angles.

For line L and M to be parallel, the two given angles must be the same.

Set them to equal each other and solve for X.

7x - 7 = 4x +14

Add 7 to each side:

7x = 4x +21

Subtract 4x from each side"

3x = 21

Divide both sides by 3:

X = 21 / 3

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5 0

3 years ago

Read 2 more answers

2/3y=27 how do i figure out what 2/3y=27 is?

saveliy_v [14]

Answer:

y=40.5

Step-by-step explanation:

you need to get y out of a fraction, to do so multiply by the denominator on both sides

3(2/3y) = 3(27)

then divide to solve for y

2y = 81

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3 years ago

Hakim was feeling adventurous at lunch. Rather than choosing a single drink, he decided to

mojhsa [17]

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3 years ago

Find the slope and the y-intercept of the line.

baherus [9]

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2 years ago

How do you graph -1/5x-1 and 4/5x-6

kakasveta [241]

Answer:

The points for the given to linear equations is (5 , - 2) and (5 , - 1)

The points is plotted on the graph shown .

Step-by-step explanation:

Given as :

The two linear equation are

y = $\dfrac{-1}{5}$ x - 1 ...........1

y = $\dfrac{4}{5}$ x - 6 ...........2

Now, Solving both the linear equations

Put the value of y from eq 2 into eq 1

I.e $\dfrac{4}{5}$ x - 6 = $\dfrac{-1}{5}$ x - 1

Or, $\dfrac{4}{5}$ x + $\dfrac{1}{5}$ x = 6 - 1

Or, $\dfrac{4 + 1}{5}$ x = 5

or, $\dfrac{5}{5}$ x = 5

∴ x = 5

Now, Put the value of x in eq 1

So, y = $\dfrac{-1}{5}$ x - 1

Or, y = $\dfrac{-1}{5}$ × 5 - 1

or, y = $\dfrac{-5}{5}$ - 1

Or, y = - 1 - 1

I.e y = -2

So, For x = 5 , y = - 2

Point is ( $x_1$ , $y_1$ ) = (5 , - 2)

Again , put the value of x in eq 2

So, y = $\dfrac{4}{5}$ x - 6

Or, y = $\dfrac{4}{5}$ × 5 - 6

Or, y = $\frac{4\times 5}{5}$ - 6

Or, y = 4 - 6

I.e y = - 2

So, For x = 5 , y = - 2

Point is ( $x_2$ , $y_2$ ) = (5 , - 2)

Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)

The points is plotted on the graph shown . Answer

5 0

3 years ago