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3 years ago

Help please i need to get this done

Mathematics

2 answers:

Vinvika [58]3 years ago

6 0

ANSWER X=4. You basically plug what y equals to into the second equation the solve for x.

Ivanshal [37]3 years ago

6 0

Answer:

x = 4

y = -7 or (-7, 4)

Step-by-step explanation:

y = -2x + 1

4x + y = 9 replace y in the second equation with (-2x + 1) since y is equal to it

4x + (-2x + 1) = 9 add like terms

2x + 1 = 9 subtract 1 from both sides

2x = 8 divide both sides by 2

x = 4 since y = -2x + 1 replace x with the value we found

y = (-2) × 4 + 1 = -7

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3 years ago

Read 2 more answers

If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func

nadya68 [22]

Answer:

a) C(1,000)=288,491.11 $

b) c(1,000)=288.49 $/u

c) dC/dx(1,000)=349.74 $/u

d) x=100 u

e) c=220 $/u

Step-by-step explanation:

(a) Find the total cost at a production level of 1000 units.

$C(x) = 2,000 + 160x + 4x^{3/2}\\\\C(1,000)=2,000 + 160(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=2,000+160,000+126,491.11= 288,491.11$

(b) Find the average cost at a production level of 1000 units.

$c(x)=C(x)/x\\\\c(1,000)=C(1,000)/1,000=288,491.11/1,000=288.49$

$\frac{dC}{dx} =0+160+4*(3/2)x^{3/2-1}=160+6x^{1/2}\\\\dC/dx|_{1,000}=160+6*(1,000)^{1/2}=160+189.74=349.74$

(d) Find the production level that will minimize the average cost.

$c=2,000x^{-1}+160+4x^{1/2}\\\\dc/dx=2,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\-2,000x^{-2}+2x^{-1/2}=0\\\\2x^{-1/2}=2,000x^{-2}\\\\x^{-1/2+2}=1,000\\\\x^{3/2}=1,000\\\\x=1,000^{2/3}=100$

(e) What is the minimum average cost?

$c(x) = 2,000/x + 160 + 4x^{1/2}\\\\C(100)=2,000/100 + 160 + 4(100)^{1/2}=20+160+40=220$

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3 years ago

Help please i need to get this done​

Help please i need to get this done