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3 years ago

What are the solutions to x^2 + 4 = -6x?

Mathematics

1 answer:

Korvikt [17]3 years ago

4 0

Answer:

Step-by-step explanation:

x² + 4 = -6x

x² + 6x + 4 = 0

quadratic formula

x = [-6±√(6²-4·1·4)]/[2·1] = [-6±√20]/2 = [-6±2√5]/2 = -3±√5

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5/9*18/25<br><br> i need help

Akimi4 [234]

Answer:

$\frac{2}{5}$

Step-by-step explanation:

$\frac{5}{9} * \frac{18}{25} = \frac{5 * 18}{9 * 25} = \frac{90}{225} = \frac{45 * 2}{45 * 5} = \frac{2}{5}$

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3 years ago

Express as a difference.

ElenaW [278]

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b: 5+5
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2 years ago

I DON"T KNOW HOW TO DO THIS! HELP!

umka21 [38]

Answer:

Second choice

Step-by-step explanation:

The sides of the new triangle is in proportion to a scale of 3 to the original triangle. Since the sides are in proportions, the triangles are similar. Thus the angles are the same.

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2 years ago

Read 2 more answers

Allan and Dave bowl together and their combined total score for one game was 375 points. Allan’s score was 60 less than twice Da

Bess [88]

A system of equations is:
B )
x + y = 375
x = 2 y - 60
We will solve this system:
2 y - 60 + y = 375
3 y = 435
y = 435 : 3
y = 145
x = 375 - 145
x = 230
Allan`s score was 230 and Dave`s score was 145.

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2 years ago

Read 2 more answers

If $8700 is invested at 3% annual simple interest, how much should be invested at 6% annual simple interest so that the total ye

True [87]

First off, see how much 8700 as principal, yields at 3% APR
that is $\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}$

it will yield some amount

subtract that amount from 393
the difference is how much the yield will be on the 6% investment
so

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}
\\\\\\
\implies \boxed{?}\\\\
-----------------------------\\\\
\textit{how much to invest at 6\%?}
\\\\\\
$

$\bf \qquad \textit{Simple Interest Earned}\\\\
(393-\boxed{?}) = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=years\to &1
\end{cases}
\\\\\\
\textit{solve for "P", to see how much should the Principal be}\\\\
\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}$

6 0

2 years ago