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Jlenok [28]
3 years ago
9

What are the solutions to x^2 + 4 = -6x?

Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

Step-by-step explanation:

x² + 4 = -6x

x² + 6x + 4 = 0

quadratic formula

x = [-6±√(6²-4·1·4)]/[2·1] = [-6±√20]/2 = [-6±2√5]/2 = -3±√5

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5/9*18/25<br><br> i need help
Akimi4 [234]

Answer:

\frac{2}{5}

Step-by-step explanation:

\frac{5}{9} * \frac{18}{25} = \frac{5 * 18}{9 * 25} = \frac{90}{225} = \frac{45 * 2}{45 * 5} = \frac{2}{5}

4 0
3 years ago
Express as a difference.
ElenaW [278]
10

b: 5+5
c: 5+5

thats thw andeer
3 0
2 years ago
I DON"T KNOW HOW TO DO THIS! HELP!
umka21 [38]

Answer:

Second choice

Step-by-step explanation:

The sides of the new triangle is in proportion to a scale of 3 to the original triangle. Since the sides are in proportions, the triangles are similar. Thus the angles are the same.

3 0
2 years ago
Read 2 more answers
Allan and Dave bowl together and their combined total score for one game was 375 points. Allan’s score was 60 less than twice Da
Bess [88]
A system of equations is:
B ) 
x + y = 375
x = 2 y - 60
We will solve this system:
2 y - 60 + y = 375
3 y = 435
y = 435 : 3
y = 145
x = 375 - 145
x = 230
Allan`s score was 230 and Dave`s score was 145.

6 0
2 years ago
Read 2 more answers
If $8700 is invested at 3% annual simple interest, how much should be invested at 6% annual simple interest so that the total ye
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First off, see  how much 8700 as principal, yields at 3% APR
that is \bf \qquad \textit{Simple Interest Earned}\\\\&#10;I = Prt\qquad &#10;\begin{cases}&#10;I=\textit{interest earned}\\&#10;P=\textit{original amount deposited}\to& \$8700\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;t=years\to &1&#10;\end{cases}

it will yield some amount

subtract that amount from 393
the difference is how much the yield will be on the 6% investment
so

\bf \qquad \textit{Simple Interest Earned}\\\\&#10;I = Prt\quad &#10;\begin{cases}&#10;I=\textit{interest earned}\\&#10;P=\textit{original amount deposited}\to& \$8700\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;t=years\to &1&#10;\end{cases}&#10;\\\\\\&#10;\implies \boxed{?}\\\\&#10;-----------------------------\\\\&#10;\textit{how much to invest at 6\%?}&#10;\\\\\\&#10;

\bf \qquad \textit{Simple Interest Earned}\\\\&#10;(393-\boxed{?}) = Prt\quad &#10;\begin{cases}&#10;I=\textit{interest earned}\\&#10;P=\textit{original amount deposited}\to& \$\\&#10;r=rate\to 6\%\to \frac{6}{100}\to &0.06\\&#10;t=years\to &1&#10;\end{cases}&#10;\\\\\\&#10;\textit{solve for "P", to see how much should the Principal be}\\\\&#10;\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}
6 0
2 years ago
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