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Amiraneli [1.4K]
3 years ago
15

5 star rating help quick

Mathematics
2 answers:
tangare [24]3 years ago
6 0

Answer:

i think b

Step-by-step explanation:

RideAnS [48]3 years ago
4 0

Answer:

D

Step-by-step explanation:

It is the only one with the coordinates (1,15) (3,25) (5,35) (7,45)

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \
Kisachek [45]

Answer:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt}\  = -\int\limits^a_b \text{f(t) dt}

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

  • \displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx}  \int\limits^{x^2}_0 t^2+1 \text{ dt}  

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

  • \displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]
  • where u represents any function other than a variable

For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

  • \displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)  

Simplify the expression by distributing 2 and 2x inside their respective parentheses.

  • [-(8x^2 +2)] + (2x^5 + 2x)
  • -8x^2 -2 + 2x^5 + 2x

Rearrange the terms to be in order from the highest degree to the lowest degree.

  • \displaystyle2x^5-8x^2+2x-2

This is the derivative of the given integral, and thus the solution to the problem.

6 0
3 years ago
Write in full text, no files plz.
slava [35]

Answer:

108 student tickets, and 176 adult tickets were sold.

I hope I helped, and thanks for the points!

Step-by-step explanation:

7 0
3 years ago
Verify by direct substitution that the given power series is a solution of the indicated differential equation. [Hint: For a pow
shepuryov [24]

Answer:

The given power series y =\sum^{\infty}_{n=0} {(-1)^n x^{2n}} is a solution of the differential equation (1+x^2)y' + 2xy = 0

Step-by-step explanation:

This is a very trivial exercise, follow the steps below for the solution:

Step 1: Since n = 0, 1, 2, 3, 4, ........, Substitute the values of n into equation (1) below.

y =\sum^{\infty}_{n=0} {(-1)^n x^{2n}}.....................(1)

y = 1 - x^2 + x^4 - x^6 + x^8.........

Step 2: Find the derivative of y, i.e. y'

y' = -2x + 4x^3 - 6x^5 + 8x^7 .............

Step 3: Substitute y and y' into equation (2) below:

(1+x^2)y' + 2xy = 0\\\\(1+x^2)(-2x + 4x^3 - 6x^5 + 8x^7......) + 2x(1 - x^2 + x^4 - x^6 + x^8.......) = 0\\\\-2x+ 4x^3 - 6x^5 + 8x^7........ - 2x^3 +4x^5 - 6x^7 + 8x^9 ......+ 2x - 2x^3 + 2x^5 - 2x^7 + 2x^9...... = 0\\\\0 = 0

(Verified)

Since the LHS = RHS = 0, the given power series y =\sum^{\infty}_{n=0} {(-1)^n x^{2n}} is a solution of the differential equation (1+x^2)y' + 2xy = 0

6 0
3 years ago
Does this table represent a proportional relationship?
dlinn [17]
I’m pretty sure it is
5 0
3 years ago
If a line cuts the y-axis at y=-6 and the slope of the line is -10, find the equation of the line.​
sweet-ann [11.9K]

Answer:

y = - 10x - 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 10 and c = - 6, thus

y = - 10x - 6 ← equation of line

6 0
3 years ago
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