Answer:
4r ^2 +9r + 12
Step-by-step explanation:
Hope this helps! :)
P _< 172 should be correct
Answer:
16, -16, 14, and -14
Step-by-step explanation:
The easiest way of solving this question is by setting up an equation. Let's use "n" to represent any random possible integer.
n (n + 2) = 224
Simplifying:
x^2 + 2n - 224 = 0
(n + 16)(n - 14) = 0
n = -16, 16 or n = -14, 14
<u>Check:</u>
16 * 14 = 224
-16 * -14 = 224
Thus, answers of 16, -16, 14, and -14 all work correctly.
Answer:
- x < 2.5
- x > 2.5
Step-by-step explanation:
One way to do this is to try a number for x and see if it makes the inequality true. A suitable number here is x=0. This value of x is less than 2.5.
<h3>1.</h3>
For x=0, you have ...
5 > -5 . . . . . true; the solution space is x < 2.5
__
<h3>2.</h3>
For x=0, you have ...
-25 > -5(2.5)
-25 > -12.5 . . . . . false; the solution space is x > 2.5
_____
<em>Alternate solution</em>
<h3>1.</h3>
Subtract 5:
-4x > -10
Divide by -4
x < 2.5
__
<h3>2.</h3>
Divide by -5:
5 < x +2.5
Subtract 2.5
2.5 < x
x > 2.5
Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
