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ollegr [7]
3 years ago
5

Jasons cutting a 2 2/5 meter string into sections that are 3/4. how many sections can he cut

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0

Answer:

3 1/5

Step-by-step explanation:

Okay, this is a standard division problem, so our equation is:

2 2/5 ÷ 3/4

but then we have to covert the mixed number to an improper fraction:

12/5 ÷ 3/4

do the cross thingy:

4/5 x 4/1 = 16/5 = 3 1/5

So Jason can cut 3 1/5 sections or 3 if you round

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a scuba diver is swimming at a depth of -15 feet. He dives down to an area that is 5 times this depth. What is the depth of his
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Step-by-step explanation: Since it starts with a negative 15 and you are diving down then you would just multiply -15*5

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A police helicopter is flying at 150 mph at a constant altitude of 0.5 mile above a straight road. The pilot uses radar to deter
natali 33 [55]

Answer:

a) (see attached picture)

b) d, h, velocity of helicopter, dd/dt

in the direction oposite to the movement of the helicopter.

Step-by-step explanation:

In order to solve this problem we must start by drawing a diagram that will represent the situation (see attached picture). As you may see, there is a right triangle being formed by the helicopter, the car and the graound. We can use this to build the equation we are going to use to model the problem.

d^{2}=h^{2}+x^{2}

we can use this equation to find the value of x at that very time, so we can do that by solving the equation for x, so we get:

x=\sqrt{d^{2}-h^{2}}

and substitute the given values:

x=\sqrt{(1)^{2}-(0.5)^{2}}

which yields:

x=0.866mi

we know that the height of the helicopter is going to be constant, so we rewrite the equation as:

d^{2}=(0.5)^{2}+x^{2}

d^{2}=0.25+x^{2}

Next, we can go ahead and differentiate the equation so we get:

2d\frac{dd}{dt}=2x\frac{dx}{dt}

which can be simplified to:

d\frac{dd}{dt}=x\frac{dx}{dt}

we can next solve the equation for dx/dt so we get:

\frac{dx}{dt}=\frac{d}{x}*\frac{dd}{dt}

so we can now substitue te provided values so we get:

\frac{dx}{dt}=\frac{1}{0.866}*-190

so we get:

\frac{dx}{dt}=-219.40mph

the negative sign means that the x-value is decreasing.

now, this problem deals with relative velocities, so we get that:

Velocity of car about the helicopter = Velocity of the car - Velocity of the helicopter. Or:

V_{ch}=V_{c}-V_{h}

so we can solve this for the actual velocity of the car, so we get:

V_{c}=V_{ch}+V_{h}

so we get:

V_{c}=-219.40mph+150mph

which yields:

V_{c}=-69.4mph

So it has a velocity of 69.4mph in a direction oposite to the helicopter's movement.

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Step-by-step explanation:

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