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Zigmanuir [339]
4 years ago
5

What are the first 5 numbers of pie?​

Mathematics
2 answers:
DIA [1.3K]4 years ago
8 0

The answer is:

3.14159

mixas84 [53]4 years ago
5 0

Answer:

3.1415

i hope i helped

plz mark brainliest

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Construction This section of a concrete skateboard ramp has the shape of a triangular prism. Find the volume
irina [24]

Answer:

volume = 73.3ft³

value = $194.4

Step-by-step explanation:

volume of prism = (½bh)l

=(½×4×4)×9.2

=73.6ft³

value of concrete

1ft³ : $4.00

73 .6ft³ : X

X : (73.6ft³ × $4.00) ÷ 1ft³

X : $294.4

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2 years ago
Daisy Hill has saved $5,000 for her first semester of college. She plans to
Katarina [22]

Amount Daisy plans to spend on food is $625

Step-by-step explanation:

  • Step 1: Given total savings of Daisy = $5000. Find the amount spent by Daisy on her room

Amount spent on room = 3/4 of 5000 = 3/4 × 5000 = $3750

  • Step 2: Calculate the remaining amount.

Remaining amount = $5000 - $3750 = $1250

  • Step 3: Calculate the amount Daisy plans to spend on food

Amount to be spend on food = 1/2 of 1250 = 1/2 × 1250 = $625

5 0
3 years ago
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A car maintains a speed of 23 mi/h for 5 seconds. It then accelerates to a speed of 46 mi/h in 5 seconds. It maintains that spee
Vika [28.1K]
The answer is a because it starts at 0 then goes up to 23 and then it goes up to 46.
6 0
3 years ago
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I need the answer. Please help.
Marysya12 [62]

Using the Pythagorean theorem:

WY =√(5^2 + 12^2)

WY = √(25 +144)

WY = √169

WY = 13 mm

7 0
3 years ago
Enter your answer in the provided box. what is the emf of a cell consisting of a pb2 / pb half-cell and a pt / h / h2 half-cell
s2008m [1.1K]

The emf of a cell is mathematically given as

E_{cell}  = 0.0532 v

<h3>What is the emf of a cell?</h3>

Generally, the equation for emf  is mathematically given as

Pb/Pb^2^+ //\ H / H_2

where,

Pb is lead

H is hydrogen

Pb^{2+} / Pb has a standard reduction potential of -0.126 volts, while

H_2 / H_2 has a standard reduction potential of 0.0 volts.

E_{cell }= E^0_{cell} - 0.059/n log 1/[Pb^2^+] x [H^+]^2

E_{cell} = 0.126 -  0.059/2 log 1  /  [0.57] x [0.09]^2

E_{cell}  = 0.0532 v

Read more about emf

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