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2 years ago

Why is it so easy to get rid of our happiness but so hard to get rid of our sadness?

Mathematics

2 answers:

tester [92]2 years ago

8 0

Answer:

nah it's easy to get rid of sadness just think of why you were happy than think of who or what makes you happy

lutik1710 [3]2 years ago

8 0

Can I know is this a question for ur studies? or u r just asking in ur leisure time.

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The standard deviation of the data set is 2.3. Compute the variance to the nearest hundredth. 2,2,2,3,5,5,6,7,8

Arada [10]

The standard deviation is the square root of the variance...so that means the variance is the standard deviation squared.

2.3^2 = 5.29 <===

7 0

3 years ago

Aimee must add together the following numbers:3.50 + 4.00 + (−1.25) + (−7.50) + 5.25 + 2.00As her first step, Aimee writes:(3.50

vladimir2022 [97]

The answer is 'C' Aimee used the Associative and Commutative Properties to put numbers that are easy to add next to each other.

I hope you have a nice day!

8 0

3 years ago

Read 2 more answers

The denominator of a rational numbers is twice it’s numerator if the numerator is decreased by 3 and the denominator increased b

ASHA 777 [7]

Answer:

$\frac{29}{58}$

Step-by-step explanation:

let x be the numerator of the rational number then 2x is the denominator

original fraction = $\frac{x}{2x}$

subtracting 3 from numerator and adding 7 to denominator , gives

$\frac{x-3}{2x+7}$ = $\frac{2}{5}$ ( cross- multiply )

5(x - 3) = 2(2x + 7) ← distribute parenthesis on both sides )

5x - 15 = 4x + 14 ( subtract 4x from both sides )

x - 15 = 14 ( add 15 to both sides )

x = 29

rational number = $\frac{29}{58}$

8 0

2 years ago

Solve x + 3y = 9 3x – 3y = -13 (1 point)

Mariana [72]

Answer:

The values of x and y to the given equations are x=-1 and $y=\frac{10}{3}$

The solution is (-1, $\frac{10}{3}$ )

Step-by-step explanation:

Given equations are $x+3y=9\hfill (1)$

and $3x-3y=-13\hfill (2)$

to solve the given equations by elimination method :

Adding the given two equations (1) and (2) we get

$x+3y=9$

$3x-3y=-13$

_______________

4x=-4

$x=-\frac{4}{4}$

Therefore x=-1

Now substitute the value x=-1 in equation(1) we get

(-1)+3y=9

3y=9+1

$y=\frac{10}{3}$

Therefore the values of x and y to the given equations are x=-1 and $y=\frac{10}{3}$

The solution is (-1, $\frac{10}{3}$ )

8 0

3 years ago

Which statement is true? A. 2x – 1 = 13 and x = 6 B. 2x – 1 = 13 and x = 7 C. 2x + 1 = 13 and x = 7 D. 2x – 1 = 13 and x = 11

alexandr1967 [171]

Answer:

B. 2x – 1 = 13 and x = 7

Step-by-step explanation:

We are given 4 equations and a solution for each. We have to tell which of the given solution satisfies the given equation.

Option A.

2x -1 = 13 and x = 6

Using this value in the equation, we get:

2(6) -1 = 13

12 - 1 = 13

11 = 13, which is not true. Hence this option is not valid

Option B.

2x - 1 = 13 and x = 7

Using the value in the equation, we get:

2(7) - 1 =13

14 - 1 =13

13 = 13, which is true. Hence this option is valid.

Option C.

2x + 1 =13 and x = 7

Using the value in the equation, we get:

2(7) + 1 = 13

15 = 13, which is not true. So this option is not valid

Option D.

2x - 1 = 13 and x = 11

Using this value in the equation, we get:

2(11) - 1 = 13

21 = 13, which is not true. Hence this option is not valid.

6 0

3 years ago