Please help i will give branliest!!!

Mathematics

1 answer:

Pepsi [2]3 years ago

5 0

Answer:b

Step-by-step explanation:

3.5*5*.5=8.75

You might be interested in

What is the result of converting 20 ounces into pounds

In-s [12.5K]

20 ounces converts to 1.25 pounds.
(Hope this helps you! Feel free to message me if you have any additional questions. :) Have a nice day!)

5 0

3 years ago

Read 2 more answers

Write the following expression using symbolic language.

Ad libitum [116K]

Answer:

<h3> 1) 7x - 5 </h3><h3> 2) 9y - 18 </h3><h3> 3) 0.5n + 4n </h3><h3> 4) 2(w³+23)</h3><h3> Step-by-step explanation:</h3>

The product of seven and a number x: 7·x = 7x

<u>Five less than the product of seven and a number x:</u>

nine times a number y: 9·y = 9y

<u>The difference of nine times a number y and eighteen:</u>

half a number n: 0.5n

four times the number: 4·n = 4n

<u>Half a number n increased by four times the number:</u>

a number w cubed: w³

the sum of a number w cubed and twenty-three: w³+23

<u>Twice the sum of a number w cubed and twenty-three:</u>

5 0

3 years ago

A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent

BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

Solution also leaves the tank at a rate of 2L/hr, therefore in x hours, the amount of water that have left the tank = 2x

Hence the amount of water present in the tank at x hours is given as:

3 + 3x - 2x = 3 + x

The time taken to full the tank can be gotten from:

3 + x = 6

x = 6 - 3

x = 3 hr

$\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\ \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg$