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Jobisdone [24]
3 years ago
8

Please I really need answers.

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
I agree with the person that commented first
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The airplane Li's family will be flying on can seat up to 149 passengers. If 96 passengers are currently on the plane,
Flauer [41]

Answer:

A) 96 + x ≤ 149

Step-by-step explanation:

The airplane can hold 149 passengers.

There are already 96 passengers on board.

They can add x additional passengers, as long as they bring the total to no more than 149.

The inequality is

96 + x ≤ 149

3 0
3 years ago
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John and alisha randomly met at the local movie theater. what will affect their first impression of each other?
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How they dress, What movie they buy, and what snacks you buy
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roger has a nail that is 12 centimeters long. he measures and records the length of the nail as 15 centimeters. what is the % er
Marianna [84]
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2 years ago
Write six times ten to the second power into a decimal
antiseptic1488 [7]
0.600. If I'm wrong please tell me so I can correct my answer and recalculate it. 
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3 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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