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Jobisdone [24]
3 years ago
8

Please I really need answers.

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
I agree with the person that commented first
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Log (x+2) base 5- log (x) = log (2x-1) base 5 - log (3x-12) base 5
Vlad [161]

Answer:

x ≅ 5.44864209

Step-by-step explanation:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

3 0
3 years ago
Given the following similar triangles, find x.​
Vsevolod [243]
I’ll help if u attach the pic of the question:)
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3 years ago
Read 2 more answers
An 118 inch board is cut into two pieces. one piece is 14 inches longer than the other piece find the length of each piece
IRINA_888 [86]
Step by step, 118-14=104, you would then divide 104 by 2 giving you 52, 52+14= 66, one piece is 66 inches while the other is 52 inches, adding them together would be 118
5 0
3 years ago
Help please! Picture included about functions. Explain if you can.
slega [8]
The definition of a function is a relation where every input (x value) is paired with exactly one output (y-value). 

A. Not a function, because you have (300, 9) and (300,7). The x-value 300 is paired with two different y-values, 9 and 7. 

B. Not a function. (260, 4) and (260, 2)

C. Is a function

D. Not a function. (225, 4) and (225, 2)
3 0
3 years ago
the volume of a storage tub shaped like a rectangular prism is 24 ft cubed. The height of the top is 3 ft the width is W feet in
kondor19780726 [428]
<h2>Answer:</h2>

\boxed{W=2ft}

<h2>Step-by-step explanation:</h2>

A prism is a solid object having two identical bases, hence the same cross section along the length. Prism are called after the name of their base. On the other hand, a rectangular prism is a solid whose base is a rectangle.  Multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:

V=L\times W\times H

From the statement of the problem we know:

V=24ft^3 \\ \\ H=3ft \\ \\ W=W \\ \\ L=W+2

So:

24=(W+2)(W)(3) \\ \\ 3W(W+2)=24 \\ \\ 3W^2+6W-24=0 \\ \\ From \ the \ Quadratic \ Formula: \\ \\ W_{12}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ W_{12}=\frac{-6 \pm \sqrt{6^2-4(3)(-24)}}{2(3)} \\ \\ W_{1}=2 \\ \\ W_{2}=-4

Since we can't have negative distance, the only valid option is \boxed{W=2ft}

3 0
3 years ago
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