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tekilochka [14]
1 year ago
9

The graph of y=x^3 is transformed as shown in the graph below. Which equation represents the transformed function?

Mathematics
1 answer:
S_A_V [24]1 year ago
4 0
Y=(-x)^3-4 the last one hope this helped on time!! If u ever need help with this u can use the desomos calculator it’s perfect for graphing good luck!
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How much wrapping paper did he use ,in square inches
Paul [167]

Answer:

96.76 square inches

Step-by-step explanation:

5.2x5.2=27.04

6.7x5.2/2=17.42

17.42x4=69.68

69.68+27.04=96.76

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

6 0
3 years ago
George is twice as old as Edward, and Edward's age exceeds Robert's age by 4 years. If the sum of the three ages is at least 56
marshall27 [118]

Answer:Robert's minimum age is 11 years.

Step-by-step explanation:

Let x represent George's age.

Let y represent Edward's age.

Let z represent Robert's age.

George is twice as old as Edward. It means that

x = 2y

Edward's age exceeds Robert's age by 4 years. It means that

z = y - 4

If the sum of the three ages is at least 56 years, it means that

x + y + z ≥ 56 - - - - - - - - - - 1

Substituting x = 2y and z = y - 4 into equation 1, it becomes

2y + y + y - 4 ≥ 56

4y - 4 ≥ 56

4y ≥ 56 + 4

y ≥ 60/4

y ≥ 15

z = y - 4 = 15 - 4

z ≥ 11

8 0
3 years ago
In Game 1, Emerson struck out 30 times in 90 times at bat. In Game 2, he struck out 40 times in 120 times at bat. In Game 3, Eme
VikaD [51]

Answer:

<u>Total number of strikeouts:</u>

  • 30 + 40 + 42 = 112

<u>Total number of at bats:</u>

  • 90 + 120 + 140 = 350

<u>Hits = times - strikeouts:</u>

  • 350 - 112 = 238

<u>Percentage:</u>

  • 238/352*100% = 67.61%

7 0
3 years ago
Decide which chi-square test (goodness-of fit, homogeneity, or independence) would be most appropriate for the given situation.
sasho [114]

Answer:

C. Test for Goodness-of-fit.

Step-by-step explanation:

C. Test for Goodness-of-fit would be most appropriate for the given situation.

A. Test Of  Homogeneity.

The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.

B. Test for Independence.

The chi square  is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.

C. Test for Goodness-of-fit.

The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with  their estimates and provided that one degree of freedom is deducted for each parameter estimated.

4 0
3 years ago
Distribute the expression. <br><br> 5(2<br> s<br> 2<br> −3s+4)
Nookie1986 [14]

If it's just distribution, not solving for s (I mean I could but do you need to?):

5(2s² - 3s + 4)     Distribute/multiply 5 into (2s² - 3s + 4)

(5)2s² - (5)3s + (5)4

10s² - 15s + 20

8 0
3 years ago
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