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aalyn [17]
3 years ago
6

In a survey, 105 students like Maths, 25 didn’t like Maths, 95 didn’t like Science, 83 like Maths but not Science. Find by drawi

ng Venn-diagram. How many students like –
a. At least one subject
b. Exactly one subject
c. At most one subject​
Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

a = 118

b = 96

c = 108

Step-by-step explanation:

105 + 25 = 130

130 students

83 = maths ONLY

105 - 83 - 22

22 = maths and science

95 didnt like science

130 - 95 = 35

35 liked science

35 - 22 = 13

13 people liked science ONLY

83 + 22 + 13 = 118

130 - 118 = 12

leaving 12 as the people who like neither

130 - 22 = 108 = people who like 0 or 1 subject (at most one subject)

You might be interested in
Given a+b+c=7 and a^2+b^2+c^2=25 Find (a+b) ^2+(a+c) ^2+(b+c) ^2
marissa [1.9K]

Answer:

26.

Step-by-step explanation:

(a + b)^2 + (a+ c)^2 + (b + c)^2 =   a^2 + b^2 - 2 ab + a^2 + c^2 - 2ac + b^2 + c^2 - 2bc

= 2( a^2 + b^2  + c^2 ) - 2( ab + ac + bc)

=<em>  </em><em>5</em>0 - 2(ab + ac + bc).............. (1).

(a + b + c)^2 = a^2 + ab + ac + ab + b^2 + bc + ac + bc + c^2

= a^2 + b^2 + c^2 + 2(ab + ac + bc)

= 25 + 2(ab + ac + bc)

But (a + b + c)^2 = 7^2 = 49. So:-

49 = 25 + 2(ab + ac + bc)

2(ab + ac + bc) = 49 - 25 = 24.

Substituting for this  in (1) above:

(a + b)^2 + (a + c)^2 + (b + c)^2 =  50 - 24 = 26 (answer).

8 0
3 years ago
The output is four times the input
juin [17]
O=4i (is that was you were asking about) 

edit: sorry that wasn't very detailed say if the input is 4 the output will be 16 or if the input is 100 the output will be 400. So mainly what ever the input is multiply it by 4.

I hope this helps :)
5 0
3 years ago
you put $1,200. in a savings account for four years at 5.6%. what is the total amount in the account after the four years
Greeley [361]

Answer:

you would have 1,194.4

Step-by-step explanation:

i subtracted.

4 0
3 years ago
I am going to get a b in abstract algebra do i suck at math
I am Lyosha [343]
If you are going to get a "B" then NO!
7 0
4 years ago
Read 2 more answers
Problem 1.[15 points] Suppose that a metal rod is supposed to be cut 74.0 mm. in length.The upper spec limit is set at 78.5 mm.,
valentina_108 [34]

1) The total Taguchi Quality Cost is;

<u><em>L_total = $119.2</em></u>

2) The recommendation for Mary Beth Mars because;

<u><em>She should focus more on the parking/drive complaints, pool complaints  and grounds complaints.</em></u>

Problem 1;

We are given that;

Dimension of length to be cut; D_i = 74 mm

Dimension of Length of upper spec limit; D_u = 78.5 mm

Dimension of Length of lower spec limit; D_l = 69.5 mm

Cost at which metal must be scrapped; L = $42

Let's find the unit formula to find cost for each of the 5 units sample.

T = L/(D_i - D_l)²

Plugging in the relevant values, we have;

T = 42/(74 - 69.5)²

T = 42/20.25

T = 2.074

Thus, the cost for each of the 5 units would be gotten from the formula;

L = 2.074(D_i - D_l)²

The measurement of <em>each sample</em> was given as;

75.6mm, 78.2mm, 68.7mm, 71.0mm and 73.6 mm.

Thus;

L₁ = 2.074(D_i - D_1)²

L₁ = 2.074(74 - 75.6)²

L₁ = $5.3094

Problem 1;

We are given that;

Dimension of length to be cut; D_i = 74 mm

Dimension of Length of upper spec limit; D_u = 78.5 mm

Dimension of Length of lower spec limit; D_l = 69.5 mm

Cost at which metal must be scrapped; L = $42

Let's find the unit formula to find cost for each of the 5 units sample.

T = L/(D_i - D_l)²

Plugging in the relevant values, we have;

T = 42/(74 - 69.5)²

T = 42/20.25

T = 2.074

Thus, the cost for each of the 5 units would be gotten from the formula;

L = 2.074(D_i - D_l)²

The measurement of each sample was given as;

75.6mm, 78.2mm, 68.7mm, 71.0mm and 73.6 mm.

Thus;

L₁ = 2.074(D_i - D_1)²

L₁ = 2.074(74 - 75.6)²

L₁ =  $5.30944

L₂ =  2.074(74 - 78.2)²

L₂ = $36.58536

L₃ = 2.074(74 - 68.7)²

L₃ = $58.25866

L₄ = 2.074(74 - 71)²

L₄ = $18.666

L₅ = 2.074(74 - 73.6)²

L₅ = $0.33184

Total Taguchi Quality Cost = L₁ + L₂ + L₃ + L₄ + L₅

Total Taguchi Quality Cost = $5.30944 + $36.58536 + $58.25866 + $18.666 + $0.33184

Total Taguchi Quality Cost = $119.1513

Approximating to the nearest penny gives;

Total Taguchi Quality Cost = $119.2

Problem 2;

The check sheet she has kept for the past 12 weeks is missing and so i have attached it.

From the check sheet attached we can see that;

Frequency of parking/drive complaints = 30

Frequency of pool complaints = 20

Frequency of grounds complaints = 17

Frequency of Tenant issues complaints = 14

Frequency of Electric/plumbing complaints = 5

With those frequencies, i have drawn a pareto's chart and attached it.

<em>Pareto's chart </em>is a bar graph that helps us to understand what is the priority per time. We can see from the chart that the complaint with the highest frequency is that of parking/drive which makes up around 34.88%. Then pool complaints which is 23.26% and then ground complaints which consists of 19.77%.

This 3 complaints add up to about approximately 78% which is close to 80% and thus Mary Beth Marrs is recommended to focus on these 3 issues primarily according to pareto's principle.

Read more at; brainly.com/question/17989104

4 0
2 years ago
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