The first step would be to isolate the square root on the left side. √x-6+2 = 6 √x-6 = -2+6 √x-6 = 4We would have to take away the radical on the left and square the equation. (√x-6)2 = (4)2 x-6 = 16Finally, x -22 = 0 x = 22
ωєℓℓ αℓℓ уσυ нανє тσ ∂σ ιѕ ∂ινι∂є 1,568 ву 28
ωнι¢н ωιℓℓ єqυαℓ тнє ωαℓℓ тσ вє 56 fєєт.
ι нσρє ι ¢συℓ∂ нєℓρ уσυ
This pattern appears to alternate between doubling and subtracting by 1.
To get from 3 to 6, we multiply by two.
To get from 6 to 5, we subtract one.
To get from 5 to 10, we multiply by two.
To get from 10 to 9, we subtract one.
To get from 9 to 18, we multiply by two.
To get from 18 to 17, we subtract one.
Therefore, next we need to multiply by two.
17 x 2 = 34
So, the next number is 34.
To find the number after, we subtract one.
34 - 1 = 33
Thus, the number after is 33.
In conclusion, the next two numbers are 34 and 33.
Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?
x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6
y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6
Rectangular coordinates of the point = (x,y) =(-6,6)
Answer: Option a. (-6,6) </span>
Answer:
Answer on Question #47534 – Math – Geometry
How to prove the volume formula of con is 1/3×π×r^2×h;without using
integration?
Solution.
Suppose we take a slice of the pyramid with the cone inside, from some way up
the pyramid. This will look like a square with a circle fitting inside. Radius of the
cone at this point, will be x.
The area of the circle is
The area of the square is × =
The ratio of the circle to the square is
.
The same is true for every slice we take: the area of the circle is
of the area
of the square.
So, the volume of the cone will be
the volume of the pyramid.
The pyramid's volume is
.
So the cone's volume is
∗
=
