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2 years ago

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Mason takes his pulse. He counts 48 beats in 2/3 minute. Mason goes on a bike ride and takes his pulse again. Now he counts 81 b

eats in 3/4 minute. How many beats per minute did Masons heart rate increase

1 answer:

Kazeer [188]2 years ago

5 0

Answer:

Therefore, beats per minute did increase for 36.

Step-by-step explanation:

48: 2/3=x:1

48=2/3 × x

x=3/2×48

x=72

81:3/4=x:1

81=x×3/4

x=4/3×81

x=108

Therefore, beats per minute did increase for 36.

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One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago

Domain and range and function or not<br><br>

aksik [14]

Answer:

Domain: -2,0,1,3,4

Range: 2,3

Yes its a function

Step-by-step explanation:

4 0

3 years ago

Help me with these questions

Elena L [17]

Answer: a = 4, b = 163,422

<u>Step-by-step explanation:</u>

$P = P_{0} e^{kt}$ P is the new population, P₀ is the initial population, k is the growth rate, t is the time elapsed.

Part a) What do we know?

P = 7003

P₀ = unknown

k = .21 <em>(converted 21% into a decimal)</em>

t = 36 yrs <em>(2006 - 1970) </em>

$P = P_{0} e^{kt}$ <em>need to solve for P₀</em>

$7003 = P_{0} e^{(.21)(36)}$

$7003 = P_{0} e^{7.56}$

7003 = P₀ (1920)

$\frac{7003}{1920} = P_{0}$

3.6 = P₀

rounded to the nearest whole number = 4

Part b) What do we know?

P = unknown

P₀ = 7003

k = .21 <em>(converted 21% into a decimal)</em>

t = 15 yrs <em>(2021 - 2006) </em>

$P = P_{0} e^{kt}$ <em>need to solve for P₀</em>

$P = 7003 e^{(.21)(15)}$

$P = 7003 e^{3.15}$

P = 7003(23.33)

P = 163,422.46

rounded to the nearest whole number = 163,422

*************************************************************

Answer: 2, -1

<u>Step-by-step explanation:</u>

eˣ² = eˣ * e²

eˣ² = eˣ⁺²

x² = x + 2

x² - x - 2 = 0

(x - 2)(x + 1) = 0

x - 2 = 0 or x + 1 = 0

x = 2 or x = -1

Check both answer for validity:

eˣ² = eˣ⁺²

e⁴ = e⁴ or e¹ = e¹

TRUE TRUE

*****************************************

Answer: 0 = ln 1

<u>Step-by-step explanation:</u>

$e^{-10} = \frac{1}{e^{10}}$

$ln(e^{-10}) = ln(\frac{1}{e^{10}})$

-10 = ln 1 - 10 <em>log rules say division is subtraction</em>

0 = ln 1

5 0

2 years ago

What is the simplified value of 5x to the power of 3 over 10x squared

andrey2020 [161]

5x^3/10x^2
*Simplify 5/10 to 1/2
*simplify the exponent so that x^1 is on top
1x/2
FINAL ANSWER:
x/2

4 0

3 years ago

Find the supplement of the angle.<br> A=133 degrees.

andrey2020 [161]

The supplement is 47

7 0

3 years ago

Read 2 more answers