<span>Using the information we have
3x+4=40
Do the same to each side of the equation to eliminate for x.
3x+4=40 Minus 4 from each side
3x=40-4
3x=36
Divide 3 from each side
x=36/3
x=12
AC=3x+4
insert the value of x
3(12)+4=40
AC=40
AD=20</span>
Answer:
a) y-intercept = 17; initial design strength percentage
b) slope = 2.8; increase in that percentage each day
c) 29.6 days to 100% design strength
Step-by-step explanation:
a, b) The equation is in the form called "slope-intercept form."
y = mx + b
where the slope is m, and the y-intercept is b.
Your equation has a slope of 2.8 and a y-intercept of 17.
The y-intercept is the percentage of design strength reached 0 days after the concrete is poured. The strength of the concrete when poured is 17% of its design strength.
The slope is the percentage of design strength added each day after the concrete is poured. The concrete increases its strength by 2.8% of its design strength each day after it is poured.
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c) To find when 100% of design strength is reached, we need to solve for x:
100 = 2.8x +17
83 = 2.8x
83/2.8 = x ≈ 29.6
The concrete will reach 100 percent of its design strength in about 30 days.
Hi there....
-8f > 56
Divide both sides by -8
-8f/-8 > 56/-8
f < -7
The correct option is : B
Answer:
11,600
Step-by-step exp
the 4 in the tens place means the 6 stays the same
Answer:
Given: ∆ABC with the altitudes from vertex B and C intersect at point M, so that BM = CM.
To prove:∆ABC is isosceles
Proof:-Let the altitudes from vertex B intersects AB at D and from C intersects AC at E( with reference to the figure)
Consider ΔBMC where BM=MC
Then ∠CBM=∠MCB......(1)(Angles opposite to equal sides of a triangle are equal)
Now Consider ΔDMB and ΔCME
∠D=∠E.......(each 90°)
BM=MC...............(given)
∠CME=∠BMD........(vertically opposite angles)
So by ASA congruency criteria
ΔDMB ≅ ΔCME
∴∠DBM=∠MCE........(2)(corresponding parts of a congruent triangle are equal)
Adding (1) and (2),we get
∠DBM+∠CBM=∠MCB+∠MCE
⇒∠DBC=∠BCE
⇒∠B=∠C⇒AB=AC(sides opposite to equal angles of a triangle are equal)⇒∆ABC is an isosceles triangle .
