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julsineya [31]
2 years ago
10

When hired at a new job selling electronics, you are given two pay options: • Option A: Base salary of $10,000 a year with a com

mission of 9% of your sales • Option B: Base salary of $20,000 a year with a commission of 4% of your sales How much electronics would you need to sell for option A to produce a larger income? Enter your answer as an inequality using the variable x to represent electronics sales in dollars. Do not enter any commas in your answer.
Mathematics
1 answer:
MArishka [77]2 years ago
3 0

Using linear functions, it is found that the number of electronics that you need to sell for a larger income in option A is x > 200,000.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

Considering the <u>base salaries as the intercept and the commissions as the slope</u>, the functions are given by:

  • A(x) = 10000 + 0.09x.
  • B(x) = 20000 + 0.04x.

To produce a larger income in option A, it is needed that:

A(x) > B(x).

Hence:

10000 + 0.09x > 20000 + 0.04x

0.05x > 10000

x > 10000/0.05

x > 200,000

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

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3 years ago
A,B and C are the vertices of one triangle.
dsp73

Answer:


Step-by-step explanation:

Given: The triangle with coordinate A(4,6), B(2,-2) and C(-2,-4). D is the mid point of AB and E is the mid point of AC.

To prove: DE is parallel to BC.

Construction: Join DE.

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Now, Mid Point D has coordinates=(\frac{4+2}{2},\frac{6-2}{2})=(3,2) and Mid Point E has coordinates=(\frac{4-2}{2},\frac{6-4}{2})=(1,1)

Now, AD= \sqrt{(4-3)^{2}+(6-2)^{2}}=\sqrt{17}

DB=\sqrt{(3-2)^{2}+(2+2)^{2}}=\sqrt{17}

AE=\sqrt{(4-1)^{2}+(6-1)^{2}}=\sqrt{34}

EC=\sqrt{(1+2)^{2}+(1+4)^{2}}=\sqrt{34}

Now, \frac{AD}{DB}=\frac{AE}{EC}

=\frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{34}}{\sqrt{34}}=\frac{1}{1}

Hence, \frac{AD}{DB}=\frac{AE}{EC}

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3 years ago
Read 2 more answers
The numbers 1,6,8,13,15,20 can be placed in the circle below, each exactly once, so that the sum of each pair of numbers adjacen
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Answer:

\fbox{\begin{minipage}{4em}36 ways\end{minipage}}

Step-by-step explanation:

<em>Step 1: Re-state the problem in an easier way to set up a permutation problem</em>

"The numbers 1,6,8,13,15,20 can be placed in the circle below, each exactly once, so that the sum of each pair of numbers adjacent in the circle is a multiple of seven"

The series above can be represented again, in form of:

7a + 1, 7b - 1, 7c + 1, 7d - 1, 7e + 1, 7f - 1

with a, b, c, d, e, f are non-negative integers.

=> 3 numbers are multiply of 7 plus 1

=> 3 numbers are multiple of 7 minus 1

<em>Step 2: Perform the counting:</em>

For the 1st number, there are 6 ways to select

To satisfy that each pair of numbers creates a multiple of 7, then:

For the 2nd number, there are 3 ways left to select

For the 3rd number, there are 2 ways left to select

For the 4rd number, there are 2 ways left to select

For the 5th number, there are 1 way left to select

For the 6th number, there are 1 way left to select

=> In total, the number of possible ways to select:

N = 6 x 3 x 2 x 2 x 1 x 1 = 72

However, these numbers are located around a circle, each option is counted twice.

=> The final number of possible ways:

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Hope this helps!

:)

3 0
3 years ago
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Answer:

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a) The constants in the binomial factors will be divisors of 6 that have a sum of 5. You know that ...

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The sums of these factor pairs are 7 and 5. You want the pair 2, 3. The factors are ...

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b) The solutions to the equation are the values of x that make the factors zero:

  (x +2) = 0   ⇒   x = -2

  (x +3) = 0   ⇒   x = -3

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