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2 years ago

Solve the equation for x. 6x = –54

Mathematics

2 answers:

Romashka [77]2 years ago

4 0

Divide each term by 6 and simplify.

x = −9

Fed [463]2 years ago

3 0

Answer:

x=-9

Step-by-step explanation:

6x = –54

To find x divide both sides by 6.

6x/6 = –54/6

x= -9

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Salena, Justin, and Brandon were riding their bikes to the library after school. The library is 12 1/2 miles from school. Salena

faust18 [17]

Answer:

Salena's got to the library first

Step-by-step explanation:

12½ miles = 25/2 miles

2½ miles = 5/2 miles

5¾ miles = 23/4 miles

114 miles = 114 miles

Salena's time of arrival =

if 5/2 miles : 5 minutes

then 25/2 miles : ?

25/2 ÷ 5/2. × 5

25/2 × 2/5 × 5

25 minutes

Justin 's time of arrival=

if 23/4 miles : 12 minutes

25/2 miles : ?

25/2 ÷ 23/4 ×12

25/2 × 4/23 ×12

26 minutes approximately

Brandon 's time of arrival=

if 114 miles : 258 minutes

25/2 miles : ?

25/2 ÷114 ×258

25/2 × 1/114×258

25 × 1/57 × 258

113 minutes approximately

3 0

3 years ago

100 POINTS TO RIGHT AWNSER!!!!

makvit [3.9K]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3000586

——————————

The answer is option D) r < 5 or r > – 1.

I'm going to graph each inequality below on a number line.

A) r > 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r>5~~or~~r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

The result is found just by joining those two intervals together. Actually that compound inequality only implies

r > – 1

which does not represent all real numbers.

—————

B) r > 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r5~~or~~r$

Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.

—————

C) r < 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r$

Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.

—————

D) r < 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r-1}&\qquad\mathsf{\overset{~~~**************************~~~}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

Now all real numbers are included in the union. So this is the right choice.

Answer: option D) r < 5 or r > – 1.

I hope this helps. =)

6 0

2 years ago

The diameter of a circle is 12 inches what is the area round to the nearest hundredth

Alisiya [41]

Answer: A≈113.1in²

Step-by-step explanation:

3 0

2 years ago

Numbers with the same absolute value are__________

Radda [10]

They are either the same, or opposite number.

4 0

3 years ago

Read 2 more answers

Solve 4sin^2 x-3=0 find two values of sinx that satisfy this equation

Leviafan [203]

$4 sin^{2} x-3=0 \\ 4 sin^{2} x=3 \\ sin^{2} x= \frac{3}{4} \\ sinx= \pm \sqrt{ \frac{3}{4} } \\ sinx= \frac{ \sqrt{3} }{2} \ or \ sinx=- \frac{ \sqrt{3} }{2} \\ x= \frac{ \pi }{3} , \ \frac{2 \pi }{3} , \ \frac{4 \pi }{3} , \ \frac{5 \pi }{3}$

5 0

3 years ago