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kap26 [50]
3 years ago
11

Kaylee obtains a loan with simple interest to buy a car that costs $8,500. If Kaylee pays $1,020 in interest during the four yea

r term of the loan, what was the rate of simple interest
Mathematics
2 answers:
olasank [31]3 years ago
7 0

Answer: 3 percent

Step-by-step explanation:

andreev551 [17]3 years ago
5 0
<span>The simple interest formula is:

A = P · (1 + r · t)
where:
A = total amount
P = principal
r = rate
t = time 

Let's solve for r:
A = P + P · r · t
P · r · t = A - P

r = (A - P) / (P · t)

The quantity A - P is defined as the Interest, therefore:
r = I / (P <span>· t)
  = 1020 / (8500 </span>· 4)
  = 0.03

Therefore the rate was 3%.


</span>
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What transformation preserves orientation but not size
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Answer:Reflection

Step-by-step explanation:

reflection does not preserve orientation

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Simplify the following question<br>x+9-10=500
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Step-by-step explanation:

x+9-10=500

x-1=500

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I need help with this !!
Zanzabum

Answer:

the twins will always have the same age

Step-by-step explanation:

the equation for jasmine's age is 2(3x+6), while the equation for james's age is 3(2x+4)

2(3x+6) = 2*3x + 2*6 = 6x + 12

3(2x+4) = 3*2x + 3*4 = 6x + 12

since both have the same equation, both will be the same age when you plug in the same x value

7 0
3 years ago
What is an equation of the line that passes through the points (6, -3) and<br> (-6, -5)?
SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

The standard form of an equation for a straight line is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).

We can calculate the slope from the two given points, (6,-3) and (-6,-5).  Slope is Rise/Run, where Rise is the change in y and Run is the change in x.

From the two given points, starting at (-6,-5) and going to (6,-3):

Rise = (-3 - (-5)) = +2

Run = (6 - (-6)) = 12

Rise/Run (slope) = 2/12 or 1/6

The equation becomes y = (1/6)x + b

We can find b by enterieng either of the two given points and solving for b.  I'll pick (6,-3):

y = (1/6)x + b

-3 = (1/6)*(6) + b

-3 = 1 + b             [Now you can see why I chose (6,-3)]

b = -4

The equation is y = (1/6)x - 4

Check this with a DESMOS graph (attached).

6 0
3 years ago
Given y = log3(x + 4), what is the range?​
lora16 [44]

Answer:

The range is all real numbers.

The domain is all reals numbers that are greater than -4.

Step-by-step explanation:

y=\log_3(x+4) only exists when x+4 is positive.

You can take the log of a negative or 0 number.

So x+4>0 implies x>-4.  (I just subtract 4 on both sides.)

So the domain is x>-4. You should see this also when you graph the curve that the curve only exist to the right of -4.

Now the range.  The range is where the curve exist for the y-values.

The equivalent exponent form of y=\log_3(x+4) is 3^{y}=x+4

We can solve this for x be subtract 4 on both sides:

x=3^y-4

Now here y can be anything; there are no restrictions on the exponent.

Also if you look at the graph of y=\log_3(x+4) you should see every y getting hit by the curve (look down to up; use the y-axis as a guide).

Let's think about the inverse I found above a little more (I'm going to swap x and y).

y=3^x-4.

If we look at the domain and range of this we can just swap it to get the domain and range of y=\log_3(x+4).

y=3^x-4 is an exponential function of 3^x that has been moved down 4 units.

The range since it has been moved down 4 units is (-4,\infty).

The domain of an exponential function is all real numbers.  There are no restrictions on what you can plug in for x.

So swapping these to find the domain and range of y=\log_3(x+4):

Domain:  (-4,\infty)

Range : (-\infty,\infty)

4 0
3 years ago
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