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rosijanka [135]
3 years ago
11

Suppose a call center receives 4000 calls on average during their Friday evening shift. Next Friday several people have put in f

or time off, so the center will be staffed by 178 call center employees. When working continuously, the average call center employee can handle 22 calls per evening shift (with a standard deviation of 5 calls). Assuming the center receives its expected 4000 calls next Friday, what is the probability that the center will have enough employees to handle this call volume
Mathematics
1 answer:
luda_lava [24]3 years ago
3 0

Answer:

The probability that the center will have enough employees to handle this call volume is 0.2764

Step-by-step explanation:

Probability is defined as the ratio of favorable outcomes to the total number of outcomes.

Here the total mean expected number of outcomes=u = 4000

The favorable  expected outcomes are = x= 22* 178= 3916

The  standard deviation= σ= 5

The random variable X =178 has normal distribution with mean 4000/22 and standard deviation 5

So z= x-u/σ

Z= (3916-4000)/22/5

z= -0.764

From the table of areas under normal curve

P (  x= 3916)=  P( -0.764 ≤ Z≤ 0)

P (  x= 3916)=  0.2764

The probability that the center will have enough employees to handle this call volume is 0.2764

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