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pantera1 [17]
3 years ago
8

Jim makes the chart shown below to prove that Triangle APD is congruent to triangle BPC:

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Answer:

Given a square ABCD and an equilateral triangle DPC and given a chart with which Jim is using to prove that triangle APD is congruent to triangle BPC.

From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.


Therefore, the justification to complete Jim's proof is "SAS postulate"



Step-by-step explanation:


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Answer:

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Step-by-step explanation:

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Triangle ABC has vertices at A(−3, 4), B(4, −2), C(8, 3). The triangle translates 2 units up and 1 unit right. Which rule repres
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Answer:

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Step-by-step explanation:

Given :

Vertices of a triangle ABC are:

A(−3, 4), B(4, −2), C(8, 3)

The triangle is translated 2 units up and 1 unit right.

To find the co-ordinates of point A after translation.

Translation rules.

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(x,y)\rightarrow (x,y+c)

For shift of k units right, the translation is given as:

(x,y)\rightarrow (x+k,y)

So, it says the triangles is translated 2 units up and 1 unit right.

The translation statement is given by:

(x,y)\rightarrow (x+1,y+2)

So, co-ordinates of point A after translation is given by :

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After the translation, the coordinates of vertex A is (-2,6).

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