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2 years ago

Can you solve 8n- 4= 52

Mathematics

2 answers:

yKpoI14uk [10]2 years ago

3 0

7 is your answer sir

GarryVolchara [31]2 years ago

3 0

Answer:

Add 4 to both sides of the equation

8n-4=52

8n-4+_4=52+_4

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Find the root<br><br> X^3-125=0

Firlakuza [10]

Steps to solve:

x^3 - 125 = 0

~Add 125 to both sides

x^3 = 125

~Take cube root of both sides

x = 5

Best of Luck!

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Sophie [7]

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2 years ago

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Paul [167]

A is not a line of symmetry

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lord [1]

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Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
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\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
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sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

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