one and twelve thirty fifths Step-by-step explanation:
Answer:
The volume in such a package is 27648 in³
Step-by-step explanation:
Consider the provided information.
Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.
Let the dimension are x by x by y.
Where x is the variable for the square base package and y is the variable for length.
Thus l=x, b=x and h=y
Then the volume of the box is:
(∵V=lbh)
The maximum combined length and girth is 144.
Therefore, 

Substitute the value of y in volume of the box.



Substitute V'(x)=0.



Now apply second derivative test.

(Min)
(Max)
Hence, the maximum volume is at x=24
If x=24 then 
Substituting value of x = 24 and y = 48
gives 27648.
Hence, the volume in such a package is 27648 in³
Answer:
Step-by-step explanation:
Area=πr²
area= π(12)²
area=452.4cm²
Step-by-step explanation:
See attached picture.
First, compare the highest term of the dividend (x²) to the highest term of the divisor (x). We need to multiply the divisor by x.
When we do that, we get x² + 5x. Subtracting this from the dividend, we get -9x + 11.
Now repeat the process. Compare the highest term of the new dividend (-9x) to the highest term of the divisor (x). We need to multiply by -9.
When we do that, we get -9x − 45. When we subtract from the new dividend, we get 56.
So the quotient is x − 9, and the remainder is 56.