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Lubov Fominskaja [6]
3 years ago
5

What is one possible solution for x? 2x2=8 8 -2 6 9

Mathematics
1 answer:
Alla [95]3 years ago
4 0

Answer:

you are going to say 2(2) ×2

then 4×2=8

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If 5 hotdogs and 15 hamburgers cost 29.50 and 10 hot dogs and 15 hamburgers cost 56.25. how much are the hot dogs and how much a
Orlov [11]

Answer:

Hotdog costs $5.35 each and hamburger costs $0.18 each

Step-by-step explanation:

The difference in price between the two is the cost of 5 hotdogs.

So, $56.25 - $29.50 = $26.50

I hotdog would cost $26.50/5 = $5.35

Substituting the cost of one hotdog,

10($5.35) + 15ham = $56.25

$53.50 + 15 ham = $56.25

15 ham = $56.25 - $53.50

15 ham = $2.75

So, 1 ham = $2.75/15

= $0.18

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3 years ago
A turtle walks 78 of a mile in 50 minutes. Determine the unit rate. How far does
iren [92.7K]

A turtle walks 100 of a mile on a hour

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3 years ago
Why do you need 23 days to count from 1 to 1 million?
Katyanochek1 [597]
This question is ambiguous. The time to count to 1 million could be more or less then 23 days. However, if someone counted to 1 million in 23 days nonstop, the interval between saying the next number would be 2 seconds.
See here for more information. https://www.quora.com/How-long-does-it-take-to-count-to-one-million


5 0
4 years ago
NEED HELP QUICKLY!
Flura [38]

Answer:

......................found it

7 0
3 years ago
Read 2 more answers
A company manager for a tire manufacturer is in charge of making sure there is the least amount of defective tires. If the tire
Anestetic [448]

Answer:

0.347% of the total tires will be rejected as underweight.

Step-by-step explanation:

For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.

And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.

1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344

1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792

The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)

Using data from the normal distribution table

P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight

Hope this Helps!!!

6 0
4 years ago
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