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3 years ago

Scientific notation is written in the form a*10^n. What must be true about the a value?

Mathematics

2 answers:

Rama09 [41]3 years ago

8 0

Answer:

It has to be a single digit between 1 and 10

-Dominant- [34]3 years ago

4 0

It has to be a single digit between 1 and 10

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Explain the meaning of 0 in each situation

Damm [24]

not totally sure what you mean by explain the mean of 0, however

250 attendees = +250 from zero

loses 7 = -7 from zero

Deposit 55 = + 55 from zero

Drop 9 = -9 from zero

Austin = +425 from zero

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3 years ago

Read 2 more answers

Which value of x makes the inequality 2(8 – x) < 4 true? A. x = –16 B. x = –9 C. x = 4 D. x = 10

myrzilka [38]

Answer:

Step-by-step explanation:

If we plug in any negative number as x, the result will always be greater than 4, which rules out answers A and B

lets try plugging in 4 as x to test answer C:

2(8-4)

2(4)= 8

8 is greater than 4, therefore C is wrong.

Lets try 10 as X (answer D):

2(8-10)

2(-2)

-4

We know that -4 is less than 4, therefore it makes the inequality true! :)

6 0

3 years ago

Read 2 more answers

Which are correct representations of the inequality 6x ≥ 3 + 4(2x – 1)? Check all that apply.

telo118 [61]

Answer:

Both

1 ≥ 2x

and

6x ≥ 3 + 8x – 4

Step-by-step explanation:

Correct representations are representations which are equivalent and represent the exact same relationship. To find these, you can simplify the inequality.

6x ≥ 3 + 4(2x – 1)

6x ≥ 3 + 8x - 4

6x ≥ 8x - 1

-2x ≥ -1

2x ≤ 1

x ≤ 1/2

4 0

3 years ago

Joyce is helping to make wreaths for her Women’s Club to sell at a local bazaar. She will be making the bows for each wreath. Sh

jok3333 [9.3K]

Answer:

She can make 34 bows with 10 feet of ribbon left

Step-by-step explanation:

1.5x34=51

61-51=10 feet of ribbons left

51/1.5=x

4 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

4 years ago