Nah fam math hard math can solve its own problems 82773919
There is no such thing as a "kilowatt per hour". If that's actually what the question says, then it's a defective question, and you should put it away before it makes you any more confused.
A 120 watt light bulb uses exactly 0.12 kilowatt when it's turned on.
In one hour, it uses
(0.12 kilowatt) x (1 hour) = 0.12 kilowatt-hour of energy.
If energy costs $0.20 per kilowatt-hour, then the cost is
(0.12) x (0.20) = 2.4 cents. (0.024 dollar)
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Q + d = 100 so q = 100 - d
0.25q + 0.10d = 19
substitute q = 100 - d into 0.25q + 0.10d = 19
0.25q + 0.10d = 19
0.25(100 - d) + 0.10d = 19
25 - 0.25d + 0.10d = 19
-0.15d = -6
d = 40
q = 100 - 40 = 60
answer
Kitara has 60 quarters and 40 dimes
Answer:
(x²+1)(x-3)
Step-by-step explanation:
Factorize x³ + x - 3x² -3
x³-3x²+x-3
Factorize
x²(x-3)+1(x-3)
= (x²+1)(x-3)
Hence the factorized form is (x²+1)(x-3)
