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3 years ago

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Find the difference between 8/10 and -2 Show all calculations in your final answer.

1 answer:

valkas [14]3 years ago

5 0

=2 4/5

8/10+2

2+8/10=2 8/10

4/5- -2/1

(4x1)-(-2x5) divided by 5x1

=4- -10 divided by 5

=14/5

=2 4/5

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x^2-6x=-1 If the quadratic equation has real solutions, what are the solutions? Explain. Estimate irrational solutions to the ne

IgorC [24]

X^2 -6x +1 = 0
a=1
b = -6
c = 1

Use the quadratic formula
x = [-b +- sq root (b^2 -4ac)] / 2a
x = [--6 +- sq root (36 - 4)] / 2
x = [ 6 +- sq root (32)] / 2
sq root (32) = 5.657

x1 = [ 6 + 5.657] / 2
x1 = 11.657 / 2
x1 = <span> <span> <span> 5.8285 </span> </span> </span>
x1 = 5.82 (to nearest tenth)

x2 = [ 6 - 5.657] / 2
x2 = .343 / 2
x2 = .1715
x2 = .2 (to nearest tenth)

7 0

3 years ago

Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

Therefore the value of given expression is $\frac{21}{128}$ .

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3 years ago

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Answer: its not showing the

Step-by-step explanation:

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L x W x H
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Step-by-step explanation:

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