All categories

2 years ago

Find the difference between 8/10 and -2 Show all calculations in your final answer.

Mathematics

1 answer:

valkas [14]2 years ago

5 0

=2 4/5

8/10+2

2+8/10=2 8/10

4/5- -2/1

(4x1)-(-2x5) divided by 5x1

=4- -10 divided by 5

=14/5

=2 4/5

You might be interested in

An automobile tire has a diameter of about 1.7. What is the circumference

lilavasa [31]

Answer:

r = 0.85 ft
C = 5.3407075111026 ft
A = 2.2698006922186 ft²

Agenda:

r = radius
C = circumference
A = area
π = pi = 3.1415926535898
<span>√ = square root
</span>
Formula:
Circumference of a circle:

C = 2πr = πd

3 0

3 years ago

Is a pair of adjacent supplementary angles forms a right angle yes or no and why

finlep [7]

Yes because if they are the same size and they are about 45 degrees and at the same corner than yes they can

3 0

2 years ago

A company's stock begins the week with a price of $43.85 per share. THe price changes by +$2.70 each day for the first two days,

mixas84 [53]

Given:

Initial price of the stock=$43.85

Change for the first two days=+$2.70

Change for next two days=-$1.10

Last day=-$4.45

The objective is to find the price at the last day.

Let's take the price at final day as <em>x</em>.

$\begin{gathered} x=43.85+2.70+2.70-1.10-1.10-4.45 \\ x=42.6 \end{gathered}$

Hence, the price of the stock at the last day is $42.6

5 0

1 year ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$