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2 years ago

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April and Cody invest $5,000 each at their local bank. April invests at a 4% simple interest rate for three years. Cody invests

at a 4% compound interest rate, and earns $624.32 in interest. What is the difference in their account balances at the end of 3 years?

2 answers:

Afina-wow [57]2 years ago

8 0

Answer:

106.43

Step-by-step explanation:

congrats

horrorfan [7]2 years ago

8 0

Answer:

106.43

Step-by-step explanation:

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For x such that 0 < x < $\frac{\pi}{2}$ , the mathematical expression is:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2$

<u>Given the following data:</u>

$\frac{\sqrt{1 \;-cos^2x} }{sinx}$

$\frac{\sqrt{1 \;-sin^2x} }{cosx}$

In Trigonometry, you should take note of the following mathematical expression:

$sin^2x + cos^2x = 1$

Therefore, we can obtain the following:

$sin^2x = 1 - cos^2x$ ...equation 1.

$cos^2x = 1 - sin^2x$ ...equation 2.

Substituting the equations respectively, we have:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = \frac{\sqrt{sin^2x} }{sinx} + \frac{\sqrt{cos^2x} }{cosx}\\\\$

Taking the square roots, we have:

$\frac{sinx}{sinx} + \frac{cosx}{cosx} = 1 +1\\\\1+1=2$

Therefore, for x such that 0 < x < $\frac{\pi}{2}$ , the expression is:

$\frac{\sqrt{1 \;-cos^2x} }{sinx} + \frac{\sqrt{1 \;-sin^2x} }{cosx} = 1+1=2$

Read more on trigonometry here: brainly.com/question/4515552

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2 years ago

Read 2 more answers