Write the equation of a line in slope intercept form that is parallel to the line y= 1/3x + 5 and passes through (-9, 5)
1 answer:
Find the slope of line 1
The equation of line 1 is y = (1/3)x + 5
m = 1/3
Find the slope of line 2
Line 2 is parallel to line 1. Parallel lines have the same number of slope. So the slope of line 2 is 1/3
Find the slope-intercept form of equation, with m = 1/3 and (-9,5)
General formula
y - y₁ = m(x - x₁)
Input the number to the formula
y - y₁ = m(x - x₁)
y - 5 = 1/3(x - (-9))
y - 5 = 1/3 (x + 9)
y - 5 = (1/3)x + 3
y = (1/3)x + 3 + 5
y = (1/3)x + 8
The equation is y = (1/3)x + 8
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3x+6=-5-2x-6
3x=-5-2x-6-6
3x+2x=-5-6-6
5x=-17
X=-17/5
X=-3.4
The fourth term of (a+b)^5 is 10a^2b^3.
For a=w, b=-4z, this is
.. 10*(w)^2*(-4z)^3
.. = -640w^2*z^3
Answer:
C
Step-by-step explanation:
C. x=7, y=5
Answer:
Step-by-step explanation:
K = A + 17
K + A = 117
A + 17 + A = 117
2A + 17 = 117
2A = 117 - 17
2A = 100
A = 100/2
A = 50 <=== what Allen sold
K + A = 117
K + 50 = 117
K = 117 - 50
K = 67 <==== what Kay sold
Answer:
8.6
Step-by-step explanation:
VW = WX / cos (36°)
= 7 / 0.81
= 8.6