What’s the answer for A) B) C)

Help please!!!! Evaluate the expression when x = 4 and y = 9 4x+6y = ?

mote1985 [20]

Answer:

52

Step-by-step explanation:

4(4)+6(9)

16+36

52

4 0

3 years ago

Read 2 more answers

Jonathan purchased a new car in 2008 for $25,400. The value of the car has been

Nikolay [14]

Answer:

5,000

Step-by-step explanation:

SORRY IF WRONG

7 0

2 years ago

A center for medical services reported that there were 295,000 appeals for hospitalization and other services. For this group, 4

pshichka [43]

Answer:

a) 0.0025 = 0.25% probability that none of the appeals will be successful.

b) 0.0207 = 2.07% probability that exactly one of the appeals will be successful.

c) 0.9768 = 97.68% probability that at least two of the appeals will be successful

Step-by-step explanation:

For each appeal, there are only two possible outcomes. Either it is succesful, or it is not. The probability of an appeal being succesful is independent of other appeals, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

45% of first-round appeals were successful.

This means that $p = 0.45$

Suppose 10 first-round appeals have just been received by a Medicare appeals office.

This means that $n = 10$

(a) Compute the probability that none of the appeals will be successful.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.45)^{0}.(0.55)^{10} = 0.0025$

0.0025 = 0.25% probability that none of the appeals will be successful.

(b) Compute the probability that exactly one of the appeals will be successful.

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}.(0.45)^{1}.(0.55)^{9} = 0.0207$

0.0207 = 2.07% probability that exactly one of the appeals will be successful.

(c) What is the probability that at least two of the appeals will be successful

This is $P(X \geq 2)$

Either less than two appeals are succesful, or at least two are. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0025 + 0.0207 = 0.0232$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.0232 = 0.9768$

0.9768 = 97.68% probability that at least two of the appeals will be successful

6 0

2 years ago

Sabendo que x2 + y2=74 e que xy=35, calcule valor de (x - y2)2

Ann [662]

To solve this problem you must apply the proccedure shown below:

1. You have the following information given in the problem above:

- x²+y²=74
xy=35

2. Therefore, you have that (x-y)² is:

=(x-y)²
=x²-2xy+y²
=(x²+y²)-2xy

3. When you substitute the values given in the problem, you obtain:

=74-2(35)
=74-70
=4

4. Therefore, as you can see, the correct answer is: 4

6 0

3 years ago

Factor the equation 16x^2 -2x-5

astraxan [27]

(8x-5)(2x+1)
Check: 16x^2+8x-10x-5
16x^2-2x-5

6 0

2 years ago